复数的加减乘除C语言实现
作者:互联网
思路:
1复数的表示:用结构体实现
2复数的加减法:实部虚部分别相加减
复数的乘法:(a+bi)(c+di)=ac-bd+(ad+cb)i
复数的除法:(a+bi)(c+di)=(ac+bd)(cc+dd)+(bc-ad)(cc+d*d)
考虑分母为0的情况
3用switch语句由用户自己选择要进行的操作
4用do…while循环实现多次运算
代码实现
#include<stdio.h>
#include<math.h>
//用结构体表示复数
typedef struct
{
double realPart;
double imagPart;
/* data */
}complex;
//定义一个复数
complex assign(double a, double b);
//复数的加法
complex add(complex c1, complex c2);
//复数的减法
complex sub(complex c1, complex c2);
//复数的乘法
complex mul(complex c1, complex c2);
//复数的除法
complex div(complex c1, complex c2);
void display(complex c);
int main()
{
double realPart, imagPart;
complex c1, c2;
int adjust=0;
do
{
printf("--------------------------------\n");
printf("欢迎您使用负数计算器\n");
printf("请您输入复数的实部和虚部\n");
scanf("%lf%lf", &realPart, &imagPart);
c1 = assign(realPart, imagPart);
display(c1);
printf("请您输入第二个复数的实部和虚部\n");
scanf("%lf%lf", &realPart, &imagPart);
c2 = assign(realPart, imagPart);
display(c2);
printf("请您选择需要进行的操作\n");
printf("1加法\n2减法\n3乘法\n4除法\n0退出复数计算器\n");
scanf("%d", &adjust);
if (adjust != 0)
{
printf("您的计算结果是:");
}
switch (adjust)
{
case 1:
display(add(c1, c2));
break;
case 2:
display(sub(c1, c2));
break;
case 3:
display(mul(c1, c2));
break;
case 4:
display(div(c1, c2));
break;
default:
if (adjust == 0)
{
printf("谢谢使用");
}
else
{
printf("输入的操作有误,请您重新输入");
}
}
} while (adjust != 0);
printf("感谢您的使用,祝您生活愉快");
return 0;
}
//定义一个复数
complex assign(double a, double b)
{
complex c;
c.realPart = a;
c.imagPart = b;
return c;
}
//复数的加法
complex add(complex c1, complex c2)
{
assign((c1.realPart + c2.realPart), (c1.imagPart + c2.imagPart));
}
//复数的减法
complex sub(complex c1, complex c2)
{
assign((c1.realPart - c2.realPart), (c1.imagPart - c2.imagPart));
}
//复数的乘法
complex mul(complex c1, complex c2)
{
assign((c1.realPart * c2.realPart - c1.imagPart * c2.imagPart), (c1.imagPart * c2.realPart + c1.realPart * c2.imagPart));
}
//复数的除法
complex div(complex c1, complex c2)
{
double temp = (pow(c1.imagPart, 2) + pow(c2.imagPart, 2));
if (c2.imagPart!=0&&c2.realPart!=0)
{
assign((c1.realPart * c2.realPart + c1.imagPart * c2.imagPart) / temp, (c1.imagPart * c2.realPart - c1.realPart * c2.imagPart) / temp);
}
else
{
printf("除数为0,请重新输入");
}
}
//输出复数
void display(complex c)
{
printf("%lf+%lfi\n",c.realPart,c.imagPart);
}
运行结果显示:
标签:imagPart,C语言,complex,复数,c2,c1,realPart,加减乘除 来源: https://blog.csdn.net/zf111212/article/details/120925457