C语言实现万年历
作者:互联网
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<time.h>
//判断润年
bool isLeap(int year);
//获取月份天数
int getMonthDays(int year,int month);
//函数功能:输入年月日,输出1900-1-1到该天的天数,-1位输入不合法
int Day(int y,int m,int d);
//绘制表头
void printHeader();
//绘制日历日期
void printDays(int week,int day);
//绘制表脚
void prinfFooter();
//输出菜单
void printMenu();
//绘制日历
void printCalendar(int year,int month);
//重新输入时间
void resetDate();
//下月
void nextMonth();
//上月
void lastMonth();
//获取当前年份月份
void getNowDate();
int year,month;
int main(){
getNowDate();
printCalendar(year,month);
while(1){
printMenu();
}
return 0;
}
void getNowDate(){
time_t timep;
struct tm *p;
time(&timep);
p = gmtime(&timep);
year = 1900 + p->tm_year;
month = 1 + p->tm_mon;
// printf("%d %d %d:", (1900 + p->tm_year), (1 + p->tm_mon), p->tm_mday);
// printf("%d;%d;%d ", p->tm_hour+8, p->tm_min, p->tm_sec);
return;
}
void printCalendar(int year,int month){
int m = getMonthDays(year,month);
int d = Day(year,month,1) % 7;
printHeader();
printDays(d - 1,m);
prinfFooter();
}
//重新输入时间
void resetDate(){
printf("请输入年、月(用空格隔开):");
scanf("%d %d",&year,&month);
printCalendar(year,month);
}
//下个月
void nextMonth(){
month = month + 1;
if(month == 13){
month = 1;
year = year + 1;
}
printCalendar(year,month);
}
//上个月
void lastMonth(){
month = month - 1;
if(month == 0){
month = 12;
year = year - 1;
}
printCalendar(year,month);
}
void printMenu(){
printf("1、重新输入时间\n");
printf("2、下个月\n");
printf("3、上个月\n");
printf("4、退出程序\n");
printf("请选择:");
int choose;
scanf("%d",&choose);
system("CLS");
switch(choose){
case 1:
resetDate();
break;
case 2:
nextMonth();
break;
case 3:
lastMonth();
break;
case 4:
exit(1);
break;
default:
printf("请选择正确选项!!!\n");
break;
}
}
void printHeader(){
printf("\t\t%d年%d月\t\n",year,month);
printf(" -------------------------------------------------------\n");
printf("|*******************************************************|\n");
printf("|-------------------------------------------------------|\n");
printf("|星期日\t星期一\t星期二\t星期三\t星期四\t星期五\t星期六 |\n");
printf("|-------------------------------------------------------|\n");
return ;
}
void prinfFooter(){
printf("\n|-------------------------------------------------------|\n");
printf("|*******************************************************|\n");
printf("|-------------------------------------------------------|\n");
}
void printDays(int week,int day){
printf("|");
if(week == -1) week = 0;
for(int i = 0; i < week; i++){
printf("\t");
}
// printf("week=%d\n",week);
for(int i = 0; i < day; i++){
if((i + week > 0) && (i + week) % 7 == 0){
printf("|\n|\n| %d\t",i + 1);
}else{
printf(" %d\t",i + 1);
}
}
return;
}
//判断润年
bool isLeap(int year){
if((year%4==0 && year%100!=0)||(year%400==0)){
return true;
}
return false;
}
//获取月份天数
int getMonthDays(int year,int month){
month = month - 1;
if(month < 0 || month > 11) return 0;
int months[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
if(isLeap(year)){
months[1] = 29;
}
return months[month];
}
//函数功能:输入年月日,输出1900-1-1到该天的天数,-1位输入不合法
int Day(int y,int m,int d)
{
int i;
int r=0; //储存1900到该天的闰年个数
int a[]={31,28,31,30,31,30,31,31,30,31,30}; //m给每出月的天数
if(y>=1900 && m>0 && m<13 && d>0 && d<32)
{
for(i=1900;i<=y;i++) //计算闰年的个数
{
if(i%400==0||i%100!=0&&i%4==0)
r++;
}
for(i=0;i<m-1;i++) //统计当年1月1日到当月的天数
{
d+=a[i];
}
if((y%400==0||y%100!=0&&y%4==0)&&m<3) //如果当年是闰年但不到二月就不能算进去
r--;
return 365*(y-1900)+r+d;
}
else
return -1;
}
标签:万年历,实现,void,printf,month,int,year,C语言,31 来源: https://blog.csdn.net/Twinkle_sone/article/details/120897066