PTA之1011 A+B 和 C (15 分)
作者:互联网
通过代码:
#include<iostream>
using namespace std;
int main()
{
long long *a,*b,*c;
int n;
cin>>n;
a=new long long [n];
b=new long long [n];
c=new long long [n];
for(int i=0;i<n;i++)
{
cin>>a[i]>>b[i]>>c[i];
if(a[i]+b[i]>c[i])
{
cout<<"Case #"<<i+1<<": true"<<endl;
}
else
{
cout<<"Case #"<<i+1<<": false"<<endl;
}
}
return 0;
}
标签:std,15,cout,int,cin,long,PTA,new,1011 来源: https://www.cnblogs.com/qingfeng66/p/15390499.html