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6-185 计算两个复数之积 (15 分)

作者:互联网

本题要求实现一个计算复数之积的简单函数。

函数接口定义:

struct complex multiply(struct complex x, struct complex y);

其中struct complex是复数结构体,其定义如下:

struct complex{
    int real;
    int imag;
};

裁判测试程序样例:

#include <stdio.h>

struct complex{
    int real;
    int imag;
};

struct complex multiply(struct complex x, struct complex y);

int main()
{
    struct complex product, x, y;

    scanf("%d%d%d%d", &x.real, &x.imag, &y.real, &y.imag);
    product = multiply(x, y);
    printf("(%d+%di) * (%d+%di) = %d + %di\n", 
            x.real, x.imag, y.real, y.imag, product.real, product.imag);

    return 0;
}

/* 你的代码将被嵌在这里 */

输入样例:

3 4 5 6

输出样例:

(3+4i) * (5+6i) = -9 + 38i

代码:

struct complex multiply(struct complex x, struct complex y)
{
    struct complex product;
    product.real=x.real*y.real-x.imag*y.imag;
    product.imag=x.real*y.imag+y.real*x.imag;
    return product;
}

标签:real,product,15,struct,int,imag,之积,complex,185
来源: https://blog.csdn.net/qq_57321225/article/details/119421795