Lambda表达式的使用，集合元素排序，如果按工资降序排序，如果工资相同，按年龄升序排序，如果年龄相同，按姓名排序

代码

public static void main(String[] args) {
        List<Student1> list = new ArrayList<>();
        Student1 student1 = new Student1("张三", 23, 6060);
        Student1 student2 = new Student1("李四", 24, 8000);
        Student1 student3 = new Student1("王五", 23, 3000);
        Student1 student4 = new Student1("赵六", 26, 3000);
        list.add(student1);
        list.add(student2);
        list.add(student3);
        list.add(student4);

        Collections.sort(list,(stu1,stu2)->{
            if (stu1.getSalary()==stu2.getSalary()){
                return Integer.compare(stu1.getAge(),stu2.getAge());
            } if (stu1.getAge()==stu2.getAge()){
                return stu1.getName().compareTo(stu2.getName());
            }else {
                return -Integer.compare(stu1.getSalary(),stu2.getSalary());
            }
        });
        list.stream().forEach(System.out::println);
        }

遍历集合的结果

Student1(name=李四, age=24, salary=8000)
Student1(name=张三, age=23, salary=6060)
Student1(name=王五, age=23, salary=3000)
Student1(name=赵六, age=26, salary=3000)

标签：stu2,stu1,Student1,list,升序,new,年龄,排序
来源： https://blog.csdn.net/lz13995976371/article/details/119347026