【计算几何】三点求角度

#include <iostream>
#include <cmath>
#define M_PI acos(-1.0)
using namespace std;

/*
get angle ACB, point C is the center point
A(x1,y1)
B(x2,y2)
C(x3,y3)
*/
double get_angle(double x1, double y1, double x2, double y2, double x3, double y3) {
	double theta = atan2(x1 - x3, y1 - y3) - atan2(x2 - x3, y2 - y3);
	if (theta > M_PI)
		theta -= 2 * M_PI;
	if (theta < -M_PI)
		theta += 2 * M_PI;

	theta = abs(theta * 180.0 / M_PI);
	return theta;
}

int main() {
	double x1 = 0;
	double y1 = 1;
	double x2 = 1;
	double y2 = 0;
	double x3 = -1;
	double y3 = -2;
	double angle1 = get_angle(x3, y3, x1, y1, x2, y2);
	double angle2 = get_angle(x1, y1, x2, y2, x3, y3);
	double angle3 = get_angle(x2, y2, x3, y3, x1, y1);
	cout << angle2 << endl;
	cout << angle3 << endl;
	cout << angle1 << endl;

	return 0;
}

标签：三点,double,x3,角度,几何,y1,theta,y3,y2
来源： https://www.cnblogs.com/Tecode/p/15086162.html