基础训练 龟兔赛跑预测

龟兔赛跑预测

/****************根据题目这里的时间一定是整数，且题目说了l一定是v1和v2的整数倍*************/
#include<iostream>
using namespace std;
int main(){
    int v1, v2, t, s, l, s1=0, s2=0, sec=0, t1, t2, tag1=0, tag2=0;
    cin>>v1>>v2>>t>>s>>l;
    while(s1<l||s2<l){
        if(s1-s2>=t){
            for(int i=1; i<=s; i++){
                sec++;
                s2+=v2;
                if(s2>=l&&tag2==0){
                    t2=sec; tag2=1;
                } 
            }
        }else{
            sec+=1;
            s1+=v1;
            s2+=v2; 
        }
        if(s1>=l&&tag1==0){
            t1=sec; tag1=1;
        }
        if(s2>=l&&tag2==0){
            t2=sec; tag2=1;
        } 
    }
    if(t1==t2) cout<<"D"<<endl<<t1<<endl;
    else if(t1<t2) cout<<"R"<<endl<<t1<<endl;
    else cout<<"T"<<endl<<t2<<endl;
    return 0;
} 

标签：赛跑,tag2,s1,龟兔,t2,v2,v1,基础训练,sec
来源： https://www.cnblogs.com/A-Little-Nut/p/10349236.html