3.八锁现象
作者:互联网
问题一,二
//1.标准情况下,两个线程先打印发短信还是打电话 1/send 2/call-----》send //2.send延迟4秒,两个线程先打印发短信还是打电话 1/send 2/call-----》先等4秒再send //回答:因为有锁的存在,synchronized锁的对象是方法的调用者,因为再这个方法中对象只有一个phone, // 也就是同一把锁,所以谁先拿到锁谁就先执行 public class Test1 { public static void main(String[] args) { Phone phone=new Phone(); new Thread(()->{phone.send();},"A").start(); try { TimeUnit.SECONDS.sleep(1); }catch (InterruptedException e){ e.printStackTrace(); } new Thread(()->{phone.call();},"B").start(); } } class Phone{ public synchronized void send(){ try { TimeUnit.SECONDS.sleep(4); }catch (InterruptedException e){ e.printStackTrace(); } System.out.println("send"); } public synchronized void call(){ System.out.println("call"); } }
问题三
//3.如下两个线程是打印send(synchronized方法)还是hello(普通方法)--》1s后打印hello 4s后打印了send //回答,hello没有锁不受锁的影响 public class Test2 { public static void main(String[] args) { Phone2 phone=new Phone2(); new Thread(()->{phone.send();},"A").start(); try { TimeUnit.SECONDS.sleep(1); }catch (InterruptedException e){ e.printStackTrace(); } new Thread(()->{phone.hello();},"B").start(); } } class Phone2{ public synchronized void send(){ try { TimeUnit.SECONDS.sleep(4); }catch (InterruptedException e){ e.printStackTrace(); } System.out.println("send"); } public void hello(){ System.out.println("hello"); } }
问题四:
//4.两个对象,两个同步方法,先send还是先call --》先call因为send睡眠了4s //回答,hello没有锁不受锁的影响 public class Test2 { public static void main(String[] args) { Phone2 phone1=new Phone2(); Phone2 phone2=new Phone2(); new Thread(()->{phone1.send();},"A").start(); try { TimeUnit.SECONDS.sleep(1); }catch (InterruptedException e){ e.printStackTrace(); } new Thread(()->{phone2.call();},"B").start(); } } class Phone2{ public synchronized void send(){ try { TimeUnit.SECONDS.sleep(4); }catch (InterruptedException e){ e.printStackTrace(); } System.out.println("send"); } public synchronized void call(){ System.out.println("call"); } }
问题五,六
//5.现在是一个对象,但是两个方法都变成了静态方法先send还是先call? 等4秒先send后call //6. 如果现在是两个对象,两个静态方法,先send还是先call? 等4秒先send后call //回答,于之前的情况来说对于静态方法,他的锁不是对象而是Class,只有唯一的一个class对象,与对象其实已经无关了 public class Test3 { public static void main(String[] args) { Phone3 phone1=new Phone3(); Phone3 phone2=new Phone3(); new Thread(()->{phone1.send();},"A").start(); try { TimeUnit.SECONDS.sleep(1); }catch (InterruptedException e){ e.printStackTrace(); } new Thread(()->{phone2.call();},"B").start(); } } class Phone3{ public static synchronized void send(){ try { TimeUnit.SECONDS.sleep(4); }catch (InterruptedException e){ e.printStackTrace(); } System.out.println("send"); } public static synchronized void call(){ System.out.println("call"); } }
问题七,八(两个对象也是打电话,两把锁是一个class模板一个对象和两个对象无关)
//对于一个普通同步方法call和一个静态同步方法send,只使用一个对象来调用,先send还是先call? // 先call,再send。两个方法使用的是两把锁,call不需要等待所以比send快 public class Test4 { public static void main(String[] args) { Phone4 phone1=new Phone4(); new Thread(()->{phone1.send();},"A").start(); try { TimeUnit.SECONDS.sleep(1); }catch (InterruptedException e){ e.printStackTrace(); } new Thread(()->{phone1.call();},"B").start(); } } class Phone4{ public static synchronized void send(){ try { TimeUnit.SECONDS.sleep(4); }catch (InterruptedException e){ e.printStackTrace(); } System.out.println("send"); } public synchronized void call(){ System.out.println("call"); } }
标签:八锁,void,send,class,现象,call,new,public 来源: https://www.cnblogs.com/wuyimin/p/14967746.html