02案例龟兔赛跑
作者:互联网
案例:龟兔赛跑
- 首先来个赛道距离,然后要离终点越来越近
- 判断比赛是否结束
- 打印出胜利者
- 龟兔赛跑开始
- 故事中时乌龟赢的,兔子需要睡觉,所以我们来模拟兔子睡觉
- 终于,乌龟赢得比赛
package edu.wzw.Thread;
public class Race implements Runnable{
private static String Winner;
@Override
public void run() {
for (int i = 1; i <= 100; i++) {
//模拟兔子睡眠
if (Thread.currentThread().getName().equals("兔子") && i%10==0){
try {
Thread.sleep(10);
} catch (InterruptedException e) {
e.printStackTrace();
}
}//模拟乌龟专属龟速
if (Thread.currentThread().getName().equals("乌龟") ){
try {
Thread.sleep(1);
} catch (InterruptedException e) {
e.printStackTrace();
}
}//判断是否完成比赛
boolean flag=gameOver(i);
if(flag){//如果比赛结束了,就停止程序
break;
}
System.out.println(Thread.currentThread().getName()+"跑了"+i+"米");
}
}//判断是否完成比赛
private boolean gameOver(int step) {
if (Winner != null) {//判断是否有胜利者
return true;
}
{
if (step >= 100) {
Winner = Thread.currentThread().getName();
System.out.println("百米冠军是 " + Winner);
return true;
}
}
return false;
}
public static void main(String[] args) {
Race race = new Race();
new Thread(race,"兔子").start();
new Thread(race,"乌龟").start();
}
}
标签:02,赛跑,Winner,currentThread,Thread,getName,龟兔,兔子,乌龟 来源: https://blog.csdn.net/dekudekuku/article/details/118255564