前置

struct point { //存储点
	double x,y;
};

double cross(double x1,double y1,double x2,double y2){ //计算叉积
	return (x1*y2-x2*y1);
}

double compare(point a,point b,point c) { //计算极角
	return cross((b.x-a.x),(b.y-a.y),(c.x-a.x),(c.y-a.y));
}

atan2

快，精度问题

bool cmp1(point a,point b) {
	if(atan2(a.y,a.x)!=atan2(b.y,b.x))
		return atan2(a.y,a.x)<atan2(b.y,b.x);
	else return a.x<b.x;
}

利用叉积按极角从小到大排序

较atan2慢，精度高

bool cmp2(point a,point b) {
	point c;//原点
	c.x = 0;
	c.y = 0;
	if(compare(c,a,b)==0)//计算叉积，函数在上面有介绍，如果叉积相等，按照X从小到大排序
		return a.x<b.x;
	else return compare(c,a,b)>0;
}

先按象限从小到大排序 再按极角从小到大排序

特殊需求的时候才会用到;

bool cmp3(point a,point b) { //先按象限从小到大排序 再按极角从小到大排序
	if(Quadrant(a)==Quadrant(b))//返回值就是象限
		return cmp1(a,b);
	else Quadrant(a)<Quadrant(b);
}

汇总

#include <bits/stdc++.h>
using namespace std;

struct point { //存储点
	double x,y;
};

double cross(double x1,double y1,double x2,double y2) { //计算叉积
	return (x1*y2-x2*y1);
}

double compare(point a,point b,point c) { //计算极角
	return cross((b.x-a.x),(b.y-a.y),(c.x-a.x),(c.y-a.y));
}

bool cmp1(point a,point b) {
	if(atan2(a.y,a.x)!=atan2(b.y,b.x))
		return atan2(a.y,a.x)<atan2(b.y,b.x);
	else return a.x<b.x;
}

bool cmp2(point a,point b) {
	point c;//原点
	c.x = 0;
	c.y = 0;
	if(compare(c,a,b)==0)//计算叉积，函数在上面有介绍，如果叉积相等，按照X从小到大排序
		return a.x<b.x;
	else return compare(c,a,b)>0;
}

int Quadrant(point a)　　 { //象限排序，注意包含四个坐标轴
	if(a.x>0&&a.y>=0)  return 1;
	if(a.x<=0&&a.y>0)  return 2;
	if(a.x<0&&a.y<=0)  return 3;
	if(a.x>=0&&a.y<0)  return 4;
}


bool cmp3(point a,point b) { //先按象限从小到大排序 再按极角从小到大排序
	if(Quadrant(a)==Quadrant(b))//返回值就是象限
		return cmp1(a,b);
	else Quadrant(a)<Quadrant(b);
}

int main() {



	return 0;
}

标签：return,point,double,atan2,极角,排序,模板
来源： https://www.cnblogs.com/Tecode/p/14853620.html