mysql查询今天、昨天、本周、本月、上一月 、今年数据
作者:互联网
本文引用自:https://www.cnblogs.com/shuilangyizu/p/8805384.html
--今天 select * from 表名 where to_days(时间字段名) = to_days(now()); --昨天 SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1 --本周 SELECT * FROM 表名 WHERE YEARWEEK( date_format( 时间字段名,'%Y-%m-%d' ) ) = YEARWEEK( now() ) ; --本月 SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) ,'%Y%m' ) --上一个月 SELECT * FROM 表名 WHERE PERIOD_DIFF(date_format(now(),'%Y%m'),date_format(时间字段名,'%Y%m') =1 --本年 SELECT * FROM 表名 WHERE YEAR( 时间字段名 ) = YEAR( NOW( ) ) --上一月 SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 时间字段名, '%Y%m' ) ) =1 --查询本季度数据 select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now()); --查询上季度数据 select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER)); --查询本年数据 select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW()); --查询上年数据 select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year)); --查询当前这周的数据 SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now()); --查询上周的数据 SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1; --查询当前月份的数据 select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m') --查询距离当前现在6个月的数据 select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now(); --查询上个月的数据 select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m') select * from ` user ` where DATE_FORMAT(pudate, ' %Y%m ' ) = DATE_FORMAT(CURDATE(), ' %Y%m ' ) ; select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now()) select * from user where MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now()) select * from [ user ] where YEAR (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = YEAR (now()) and MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now()) select * from [ user ] where pudate between 上月最后一天 and 下月第一天 where date(regdate) = curdate(); select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now()) SELECT date( c_instime ) ,curdate( ) FROM `t_score` WHERE 1 LIMIT 0 , 30
标签:www,days,--,一月,mysql,DAYS,查询,表名,字段名 来源: https://www.cnblogs.com/gxlaqj/p/13929967.html