通过 Bean Searcher 在数据库中对数据的排序
作者：互联网
想要H5页面中实现升序,降序的排序功能 :
问题 :
点击排序按钮只可以降序,不能升序
原因 :
小于0时无法排序, 原因是返回值为 int 类型, 小于0的值变为0,所以无法排序
但是在解决这个问题同时发现了另外一个问题, 因为要做分页处理(每页数据为15条), 数据超过15条数据时, 那么排序只会排当前页查到的数据, 前面页码数据不参与排序
所以需要在数据库中排序 而不能在 代码中排序(在代码中排序需要将所有数据全部查询出来, 数据过大时会对数据产生影响,不建议使用)
代码 :
1 @Secured('permitAll')
2 def piles(Integer page, Integer size, String searchTerm, String sort, String order, Boolean online) {
3 page = page ?: 0
4 size = size ?: 15
5 sort = sort ?: 'income'
6 order = order ?: 'desc'
7 def user = securityService.currUser
8 def piles = ChargePile.createCriteria().list {
9 eq 'deleted', false
10 if (online) {
11 eq 'status', ModelConst.CHARGE_PILE__STATUS__ONLINE
12 } else {
13 eq 'status', ModelConst.CHARGE_PILE__STATUS__OFFLINE
14 }
15 chargeSite {
16 eq 'platform', PlatformHolder.loadPlatform()
17 eq 'status', ModelConst.CHARGE_SITE__STATUS__APPROVED
18 agent {
19 eq 'user', user
20 }
21 }
22 if (searchTerm) {
23 searchTerm = '%' + searchTerm + '%'
24 or {
25 ilike 'pileNo', searchTerm
26 chargeSite {
27 ilike 'name', searchTerm
28 }
29 }
30 }
31 projections {
32 property 'id'
33 property 'pileNo'
34 property 'location'
35 property 'portCount'
36 chargeSite {
37 property 'name'
38 property 'address'
39 property 'addressDetail'
40 }
41 property 'status'
42 property 'type'
43 }
44 maxResults size
45 firstResult page * size
46 }.collect { Object[] it ->
47 def pileId = it[0]
48 def pile = ChargePile.load(pileId as Long)
49 def pileReport = PileReport.createCriteria().get {
50 eq 'type', ModelConst.REPORT__TYPE__DATE
51 eq 'time', TimeUtils.getYesterdayyyyyMMdd()
52 eq 'chargePile', pile
53 } as PileReport
54 [
55 id : pileId,
56 pileNo : it[1],
57 total : it[3],
58 siteName: it[4],
59 address : AddressUtils.getFullAddress(it[5] as District, it[6] as String).concat(it[2] as String),
60 status : it[7],
61 busy : it[7] == ModelConst.CHARGE_PILE__STATUS__ONLINE ? pileCacheService.busyPortCount(it[0] as long, it[3] as int) : 0,
62 broken : it[7] == ModelConst.CHARGE_PILE__STATUS__ONLINE ? pileCacheService.brokenPortCount(it[0] as long, it[3] as int) : 0,
63 avaliable : it[7] == ModelConst.CHARGE_PILE__STATUS__ONLINE ? pileCacheService.avaliablePortCount(it[0] as long, it[3] as int) : 0,
64 usedRate: pileReport ? String.format('%.2f', pileReport?.useRate * 100) : '0', // 排序字段
65 income : pileReport ? String.format('%.2f', pileReport?.pileIncomeAmount / 100) : '0.00', // 排序字段
66 ]
67 } as List
68 def result = [
69 piles: listSort(piles, sort, order), // 上述图片中方法
70 online: countPiles(ModelConst.CHARGE_PILE__STATUS__ONLINE),
71 offline: countPiles(ModelConst.CHARGE_PILE__STATUS__OFFLINE)
72 ]
73 render result as JSON
通过 Bean Searcher 在数据库中进行排序 代码如下 :
1 @SearchBean(tables = '''charge_pile p // sql语句
2 left join pile_report r on r.charge_pile_id = p.id and r.type = 1 and r.time = :time // on后面是对局部条件做限制
3 left join charge_site s on p.charge_site_id = s.id
4 left join agent a on s.agent_id = a.id ''',
5 joinCond = '''p.deleted = 0 and a.user_id = :userId and s.platform_id = :platformId and // joinCond 相当于在sql中的where, where后面是对全局做限制
6 (s.name like :search or p.pile_no like :search)''') // 实现条件搜索(设备名称或设备编号)
7 class PileReportBean implements BeanAware {
8
9 @DbField('p.id')
10 Long id
11
12 @DbField('p.pile_no')
13 String pileNo
14
15 @DbField('p.location')
16 String location
17
18 @DbField('p.port_count')
19 Integer portCount
20
21 @DbField('p.status')
22 int status
23
24 @DbField('p.type')
25 int type
26
27 @DbField('s.name')
28 String name
29
30 @DbField('s.address_detail')
31 String address
32
33 @DbField('r.use_rate')
34 BigDecimal useRate
35
36 @DbField('r.pile_income_amount')
37 Integer pileIncomeAmount
38
39
40 @Override
41 void afterAssembly() {
42
43 }
44
45 }
控制层代码 :
1 @Secured('permitAll') //权限 所有人可以访问
2 def piles(Integer page, Integer size, String searchTerm, String sort, String orderMode, Boolean online) {
3 page = page ?: 0
4 size = size ?: 15
5 sort = sort ?: 'pileIncomeAmount'
6 orderMode = orderMode ?: 'desc'
7 def user = securityService.currUser
8 log.info("user:${user},")
9 def status = online ? 1 : 2
10 def params = [ // sql的 wehre 条件
11 platformId : PlatformHolder.loadPlatform().id,
12 time : TimeUtils.getYesterdayyyyyMMdd(),
13 userId : user.id,
14 status : status,
15 search : '%' +searchTerm + '%', // 搜索条件(通过前端传入)
16 sort : sort, // 排序字段(前端传入)
17 order : orderMode, // 排序方式(desc or asc)
18 max : size,
19 offset : page
20 ]
21
22 def piles = searcher.search(PileReportBean, params)
23 piles = piles.dataList?.collect { it ->
24 [
25 id : it.id,
26 pileNo : it.pileNo,
27 total : it?.portCount,
28 siteName : it.name,
29 address : it.address,
30 status : it.status,
31 busy : it.status == ModelConst.CHARGE_PILE__STATUS__ONLINE ? pileCacheService.busyPortCount(it.id, it.portCount) : 0,
32 broken : it.status == ModelConst.CHARGE_PILE__STATUS__ONLINE ? pileCacheService.brokenPortCount(it.id, it.portCount) : 0,
33 avaliable : it.status == ModelConst.CHARGE_PILE__STATUS__ONLINE ? pileCacheService.avaliablePortCount(it.id, it.portCount) : 0,
34 useRate : it.useRate ? String.format('%.2f', it?.useRate * 100) : '0',
35 pileIncomeAmount: it.pileIncomeAmount ? String.format('%.2f', it?.pileIncomeAmount / 100) : '0.00'
36 ]
37 }
38 def result = [
39 piles: piles,
40 online: countPiles(ModelConst.CHARGE_PILE__STATUS__ONLINE),
41 offline: countPiles(ModelConst.CHARGE_PILE__STATUS__OFFLINE)
42 ]
43 render result as JSON
44 }
以上 方法解决 本次所遇到的 排序问题
标签：__,Searcher,String,CHARGE,Bean,status,排序,id,ModelConst 来源： https://www.cnblogs.com/guoleidd/p/12891542.html