1.从众多事物中查询每个事物的最新时间的记录。
select c.vin,c.checktime
from (select t.*,
row_number() over(partition by t.vin order by t.checktime desc) rn
from test_table t
where t.vin is not null) c
where rn = 1;
标签：checktime,事物,vin,案例,sql,oracle,rn,where,select
来源： https://www.cnblogs.com/AWNUygah/p/12199772.html