hdu1270小希的数表-枚举（java）

关键点：
1.通过构造将num[2]+num[3]转化为sum[i],使得枚举num[2]+num[3]的过程转化为遍历sum[i]的过程
2.通过删减子区间来获得重叠子问题，以更新num

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.StreamTokenizer;
import java.util.Arrays;

public class Main {
    private static int[] sum,num ;
    private static boolean[] vis ;
    public static void main(String[] args) throws IOException {
        StreamTokenizer in = new StreamTokenizer(new BufferedReader(new InputStreamReader(System.in))) ;
        while(in.nextToken()!=StreamTokenizer.TT_EOF){
            int n = (int)in.nval ;
            if(n==0)break ;
            int m = (n-1)*n /2 ;
            sum = new int[110*110] ;
            num = new int[105] ;
            vis = new boolean[110*110] ;
            for (int i = 1; i <= m; i++) {
                in.nextToken() ;
                sum[i] = (int)in.nval ;
            }
            for(int i=3;i<=m;i++){
                num[2] = (sum[1]-sum[2]+sum[i]) / 2 ;
                num[1] = sum[1] - num[2] ;
                num[3] = sum[2] - num[1] ;
                if(num[2]+num[3]!=sum[i])continue ;
                Arrays.fill(vis,false) ;
                int start = 3 ;
                vis[i] = true ;
                boolean flag = true ;
                for(int j=4;j<=n&&flag;j++){
                    while(vis[start])start++ ;
                    num[j] = sum[start] - num[1] ;
                    vis[start] = true ;
                    for(int k=2;k<j&&flag;k++){
                        for(int x=start+1;x<=m;x++){
                            flag = false ;
                            if(!vis[x]&&num[k]+num[j]==sum[x]){
                                vis[x] = true ;
                                flag = true ;
                                break ;
                            }
                        }
                    }
                }
                if(flag)break ;
            }
            for(int i=1;i<=n;i++){
                if(i!=n){
                    System.out.print(num[i]+" ") ;
                }else{
                    System.out.println(num[n]) ;
                }
            }
        }
    }
}

标签：小希,java,hdu1270,start,int,sum,vis,num
来源： https://blog.csdn.net/sukisabishi/article/details/115426929