【数值分析】python实现复化辛普森积分

• python代码

import numpy as np

a, b = input("积分区间：").split(' ')
n = int(input("子区间个数："))

a = int(a)
b = int(b)
x_i = np.linspace(a, b, n+1) # 区间结点
h = (b-a)/n

# 原函数
def f(x):
    return 4/(1+x**2)

def piece(x_i, i, h): 
    return h/6 * (f(x_i[i-1]) + 4*f((x_i[i-1] + x_i[i])/2) + f(x_i[i]))

S = 0
for i in range(1, n+1):
    S = S + piece(x_i, i, h)

print("复化辛普森积分公式计算结果：" + str(S))

• 输入格式及测试结果
  

标签：return,python,积分,辛普森,int,复化,np,input
来源： https://blog.csdn.net/qq_51283283/article/details/115419711