Java中List的排序

场景

Bean定义如下，仅有一个类型为Integer的age字段。

@NoArgsConstructor
@AllArgsConstructor(staticName = "of")
@Data
public static class Employee {
    private Integer age;
}     

列表初始化5个元素：

List<Employee> list = new ArrayList<>();
list.add(Employee.of(21));
list.add(Employee.of(22));
list.add(Employee.of(25));
list.add(Employee.of(28));
list.add(Employee.of(23));           

排序

使用Collections中的sort方法进行排序：

Collections.sort(list, new Comparator<Employee>() {
    @Override
    public int compare(Employee o1, Employee o2) {
        return o1.getAge().compareTo(o2.getAge());
    }
});

倒序：

Collections.reverse(list);

lambda表达式

JDK8支持lambda表达式，写法更加简洁：

Collections.sort(list, (o1, o2) -> o1.getAge().compareTo(o2.getAge()));

或者使用Comparator接口：

Collections.sort(list, Comparator.comparing(Employee::getAge));

倒序：

Collections.sort(list, Comparator.comparing(Employee::getAge).reversed());

stream的sorted方法

list.stream().sorted(Comparator.comparing(Employee::getAge));

倒序：

list.stream().sorted(Comparator.comparing(Employee::getAge).reversed());

list自带的sort方法

list.sort(Comparator.comparing(Employee::getAge));

倒序：

list.sort(Comparator.comparing(Employee::getAge).reversed());

null值

假设列表中有age字段为null：

List<Employee> list = new ArrayList<>();
list.add(Employee.of(21));
list.add(Employee.of(null));
list.add(Employee.of(null));
list.add(Employee.of(28));
list.add(Employee.of(23));           

这个时候会报NPE：

-----------------------------
Exception in thread "main" java.lang.NullPointerException
    at java.util.Comparator.lambda$comparing$77a9974f$1(Comparator.java:469)
    at java.util.TimSort.countRunAndMakeAscending(TimSort.java:355)
    at java.util.TimSort.sort(TimSort.java:220)
    at java.util.Arrays.sort(Arrays.java:1512)
    at java.util.ArrayList.sort(ArrayList.java:1462)

可以使用Comparator.comparing的第2个参数：

list.sort(Comparator.comparing(Employee::getAge, Comparator.nullsLast(Comparator.naturalOrder())));
list.sort(Comparator.comparing(Employee::getAge, Comparator.nullsLast(Integer::compareTo)));
list.sort(Comparator.comparing(Employee::getAge, Comparator.nullsLast(Comparable::compareTo)));

以上3中写法都可以，注意第2个参数使用了Comparator.nullsLast让null排在最后。
与之对应的是Comparator.nullsFirst可以null排在最前。

任意字段排序

最近项目中有个这样场景，List中是个Map<String, Object>，需要支持Map的任意key排序。
完整代码如下：

import java.util.*;

/**
 * @author cdfive
 * @date 2019-05-26
 */
public class ListSortDemo2 {
    public static void main(String[] args) {
        List<Map<String, Object>> list = new ArrayList<>();
        list.add(new HashMap<String, Object>(){{put("name", "aaa");put("age", 21);}});
        list.add(new HashMap<String, Object>(){{put("name", "ccc");put("age", null);}});
        list.add(new HashMap<String, Object>(){{put("name", "ddd");put("age", null);}});
        list.add(new HashMap<String, Object>(){{put("name", "bbb");put("age", 28);}});
        list.add(new HashMap<String, Object>(){{put("name", "aaa");put("age", 23);}});

        printList(list);

        printLineSep();

        sort(list, "age", "asc");

        printList(list);
    }

    public static void sort(List<Map<String, Object>> list, String sortField, String sortDirection) {
        if ("desc".equals(sortDirection)) {
            Comparator<Map<String, Object>> comparator = Comparator.comparing(o -> (Comparable) o.get(sortField), Comparator.nullsFirst(Comparable::compareTo));
            list.sort(comparator.reversed());
        } else {
            Comparator<Map<String, Object>> comparator = Comparator.comparing(o -> (Comparable) o.get(sortField), Comparator.nullsLast(Comparable::compareTo));
            list.sort(comparator);
        }
    }

    public static void printList(List<?> list) {
        list.stream().forEach(o -> System.out.print(o));
        System.out.println();
    }

    public static void printLineSep() {
        System.out.println("-----------------------------");
    }
}

注意：
倒序使用Comparator.nullsFirst和comparator.reversed()，需要单独定义comparator变量，如果直接一行写：
list.sort(Comparator.comparing(o -> (Comparable) o.get(sortField), Comparator.nullsFirst(Comparable::compareTo)).reversed());会编译不通过。
正序使用Comparator.nullsLast。

标签：sort,Java,Comparator,List,list,comparing,add,Employee,排序
来源： https://www.cnblogs.com/cdfive2018/p/10927960.html