【Luogu3414】SAC#1 - 组合数
作者:互联网
problem
solution
codes
#include<iostream> #define mod 6662333 using namespace std; typedef long long LL; LL dfs(LL a, LL b, LL p){ if(b==1)return a%p; LL t = dfs(a,b>>1,p)%p; if(b%2==0)return t*t%p; else return t*t*a%p; } int main(){ LL n; cin>>n; cout<<dfs(2,n-1,mod); return 0; }
标签:b%,return,C#,LL,dfs,long,a%,SA,Luogu3414 来源: https://www.cnblogs.com/gwj13114/p/15556589.html