java刷题--221最大正方形

• 题目
• 代码
• 结果

题目

代码

当且仅当右下角大于等于1时构成正方形，此时右下角的值即正方形边长

class Solution {
    public int maximalSquare(char[][] matrix) {
        int maxSide = 0;
        if (matrix == null || matrix.length == 0 || matrix[0].length == 0) return maxSide;
        int rows = matrix.length, columns = matrix[0].length;
        int[][] dp = new int[rows][columns];
        for (int i = 0; i < rows; i++) {
            for (int j = 0; j < columns; j++) {
                if (matrix[i][j] == '1') {
                    if (i == 0 || j == 0) {
                        dp[i][j] = 1;
                    } else {
                        dp[i][j] = Math.min(Math.min(dp[i - 1][j], dp[i][j - 1]), dp[i - 1][j - 1]) + 1;
                    }
                    maxSide = Math.max(maxSide, dp[i][j]);
                }
            }
        }
        int maxSquare = maxSide * maxSide;
        return maxSquare;
    }
}

结果

标签：java,matrix,maxSide,正方形,--,int,length,221,dp
来源： https://blog.csdn.net/Anrys/article/details/119065680