Exception in thread "main" java.lang.NumberFormatException: For input string: "1.6262

问题还原:

public static void main(String[] args) {

String startTime ="1.626290463E12";
System.out.println("begin================"+Long.parseLong(startTime));

}

报错信息:

Exception in thread "main" java.lang.NumberFormatException: For input string: "1.626290463E12"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Long.parseLong(Long.java:589)
at java.lang.Long.parseLong(Long.java:631)
at basis.xz.stringformat.main(stringformat.java:34)

解决:

public static void main(String[] args) {
   
    String startTime ="1.626290463E12";
    //long类型十进制还原
    BigDecimal v = new BigDecimal(startTime).setScale(0,BigDecimal.ROUND_HALF_UP);
    System.out.println(Long.parseLong(v));

}

标签：lang,Exception,java,parseLong,E12,Long,main
来源： https://www.cnblogs.com/lwdwl/p/15040074.html