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postgresql 合并函数 string_agg

SELECT a.id,a.name as "companyName",a.xydm,a.fddbr,string_agg(case when d.zzlx = 1 then '路基路面'when d.zzlx = 2 then '桥梁'when d.zzlx = 3 then '隧道'when d.zzlx = 4 then '交通安全设施' end ||case when d.zzdj = 1 then