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mongodb 删除重复的数据

//PlaceName:'$PlaceName',CityCode:'$CityCode' 查询条件 //dups 查询到的重复数据    db.getCollection('HotLocation').aggregate([ { $group:{_id:{PlaceName:'$PlaceName',CityCode:'$CityCode'},count:{$sum:1},dups:{

MongoDb查询

//数据转换类型mongodb过滤数据并聚合 db.IotMeterGasUsedRecord_2020.aggregate([{ // 获取字段   $project: { _id: 0,      // 类型转换 RecordUsedValue: { $toDouble: { $substrBytes: ["$RecordUsedValue", 0, 4]

mongodb删除重复数据

注:mongodb当前版本是3.4.3 插入六条数据: 查询存在重复的数据: 查询并循环删除重复数据: 删除语句解析: db.userInfo.aggregate([ { $group: { _id: {userName: '$userName',age: '$age'},count: {$sum: 1},dups: {$addToSet: '$_id'}} }, { $match: {count: {$gt: 1}} } ]).forEa

mongo删除重复行

db.qatest2.aggregate([ { $group:{_id:{date:'$count_date',name:'$committer_name',project:'$project_name'},count: {$sum: 1},dups: {$addToSet: '$_id'}} }, { $match: {count: {$gt: 1}} } ]).forEach(function(

【leetcode】1002. Find Common Characters

  class Solution { public List<String> commonChars(String[] A) { List<String> dups = new ArrayList(); int length = A[0].length(); for(int i=0; i<length; i++) { char c = A[0].charAt(i); fo

mongodb删除重复数据

注:mongodb当前版本是3.4.3   插入六条数据:   查询存在重复的数据:   查询并循环删除重复数据:   删除语句解析: db.userInfo.aggregate([     {         $group: { _id: {userName: '$userName',age: '$age'},count: {$sum: 1},dups: {$addToSet: '$_id'}}     },