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PAT Advanced 1021 Deepest Root（25）
题目描述： A graph which is connected and acyclic can be considered a tree. The height of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root is called the deepest root. Input Specification:【数据结构】算法 层数最深叶子节点的和 Deepest Leaves Sum
目录层数最深叶子节点的和 Deepest Leaves Sum思路Tag 层数最深叶子节点的和 Deepest Leaves Sum 一棵二叉树的根节点root,返回层数最深的叶子节点的和。 in： root = [1,2,3,4,5,null,6,7,null,null,null,null,8] out：15 思路 对树的处理基本就是 DFS,BFS。 看到一个非常有意思的1302. Deepest Leaves Sum (M)
Deepest Leaves Sum (M) 题目 Given the root of a binary tree, return the sum of values of its deepest leaves. Example 1: Input: root = [1,2,3,4,5,null,6,7,null,null,null,null,8] Output: 15 Example 2: Input: root = [6,7,8,2,7,1,3,9,null,1,4,null,null,null,5需要二刷的题目
树： 1021 Deepest Root (25分) 1020 Tree Traversals (25分) 1004 Counting Leaves (30分) 大整数运算 1023 Have Fun with Numbers (20分) 1024 Palindromic Number (25分) 图： 1003 Emergency (25分) 栈和队列： 1051 Pop Sequence (25 分)LeetCode - Lowest Common Ancestor of Deepest Leaves
Given the root of a binary tree, return the lowest common ancestor of its deepest leaves. Recall that: The node of a binary tree is a leaf if and only if it has no children The depth of the root of the tree is 0. if the depth of a node is d, the depth o1021 Deepest Root(甲级)
1021 Deepest Root (25分) A graph which is connected and acyclic can be considered a tree. The height of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root is called the deepest root. IPAT Advanced 1021 Deepest Root (25分)
A graph which is connected and acyclic can be considered a tree. The height of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root is called the deepest root. Input Specification: Each i1021 Deepest Root (25分)
先用dfs数出图的连通分量数count，如果连通分量数count > 1直接输出结果； 如果count == 1，说明该图连通，又因为图中只有n - 1条边，该图必然为无环图，对每个根节点进行dfs，找出根的最大深度。 #include<cstdio> #include<unordered_set> #include<vector> #include<set> using namesPAT 1021 Deepest Root (求树的高度 图的连通块数)
A graph which is connected and acyclic can be considered a tree. The height of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root is called the deepest root. Input Specification: Each iPAT Advanced A1021 Deepest Root (25) [图的遍历，DFS，计算连通分量的个数，BFS，并查集]
题目 题目分析 已知图的顶点N和边N-1，判断所给图是否是一棵树，如果是，查找并打印最高树的所有根节点（从小到大） 判断图为树有两个条件：只有一个连通分量（否则为森林）；无环（已知顶点数为N，边为N-1的连通图一定是树） 最高树的所有根节点，其含义可以从样例中推导得出（起始顶点不同，寻找出的最高树不1021 Deepest Root (25 分)
不是原创？？？ #include <cstdio> #include <vector> #include <queue> #include <algorithm> using namespace std; vector<int> visited(10001), roots; vector<vector<int>> G(10001); int minH = 0; void BFS( int v ) { queue&l1021 Deepest Root
A graph which is connected and acyclic can be considered a tree. The height of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root is called the deepest root. Input Specification: Each iPAT 1021 Deepest Root
1021 Deepest Root (25 分) A graph which is connected and acyclic can be considered a tree. The height of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root is called the deepes1021 Deepest Root
使用邻接矩阵会有测试点超时，所以要用vector邻接表 #include<iostream> #include<cstring> #include<vector> #include<algorithm> using namespace std; const int maxn=10010; int n,m,maxdeep; vector<int> G[maxn]; int depth[maxn]; int vis[maxn]; void DFS(iPTA-1021—— Deepest Root（最后两组数据错误）
题目: A graph which is connected and acyclic can be considered a tree. The hight of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root is called the deepest root. Input Specification: Eac