Median

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PAT Advanced 1029 Median（25）

题目描述： Given an increasing sequence S of N integers, the median is the number at the middle position. For example, the median of S1 = { 11, 12, 13, 14 } is 12, and the median of S2 = { 9, 10, 15, 16, 17 } is 15. The median of two sequences is defined to be

NC50940 Running Median

题目原题地址：Running Median 题目编号：NC50940 题目类型：对顶堆时间限制：C/C++ 5秒，其他语言10秒空间限制：C/C++ 65536K，其他语言131072K 1.题目大意多组数据，每组有标号、元素个数（奇数个）以及元素，输出每组的标号、输出的个数、以及每次读到奇数个元素时已经读取的元素中的中位数，

LeetCode 295 Find Median from Data Stream

The median is the middle value in an ordered integer list. If the size of the list is even, there is no middle value and the median is the mean of the two middle values. For example, for arr = [2,3,4], the median is 3. For example, for arr = [2,3], the m

LeetCode Median of Two Sorted Arrays 排序

Given two sorted arrays nums1 and nums2 of size m and n respectively, return the median of the two sorted arrays. The overall run time complexity should be \(O(\log (m+n))\). Solution 简单排序即可：点击查看代码 class Solution { private: vector<int> vc;

NC50940 Running Median

题目链接题目题目描述 For this problem, you will write a program that reads in a sequence of 32-bit signed integers. After each odd-indexed value is read, output the median (middle value) of the elements received so far. 输入描述 The first line of input cont

codewars联系题

You are the "computer expert" of a local Athletic Association (C.A.A.). Many teams of runners come to compete. Each time you get a string of all race results of every team who has run. For example here is a string showing the individual results

R语言：调用dplyr的group_by函数不管用了

刚发现使用dplyr包进行group_by分析不管用了。 library(dplyr) library(plyr) comallte=comall %>% group_by(A,B,C,D) %>% summarise(median=median(E)) 后面发现是因为plyr和dplyr冲突了。改为以下顺序即可正常运行dplyr： library(plyr) library(dplyr) comallte=comall %>% gr

POJ-3579 Median

Median 给n组数，将其两两之差列为新的数列，求这个数列的中位数二分套二分很容易想到是二分答案，查看有多少个数小于等于这个答案抽象的地方在于查询有多少个差小于等于当前的差，通过二分\(a[i]+x\)在原数组的位置来判断，有多少个数 \(y \ge a[i] + x\)，从而判断以\(pair(a[i], y)\)的

LeetCode每日一练【4】

LeetCode每日一练 median-of-two-sorted-arrays const findMedianSortedArrays = (nums1, nums2) => { const nums = [...nums1, ...nums2].sort((a, b) => { return a - b; }); const length = nums.length; const median = Math.floor(length / 2

Salt Pepper噪声以及使用median filter来减少噪声

文章首发于个人博客：https://xydida.com/2022/2/27/ComputerVision/salt-and-pepper-noise/，转载请联系作者。处理图像时，我们用的图片往往都会有很多噪声。在黑暗中或是设备感光器受到影响，拍出来的图像就会有很多噪声，俗称“噪点”，Salt & Pepper就是其中一种。为什么会叫盐和胡椒粉？

4. Median of Two Sorted Arrays

This problem can be solved by using two PriorityQueue(s), which is just the same solution as 295. Find Median from Data Stream. PriorityQueue<Integer> smallQ = new PriorityQueue<>((x, y) -> y - x); PriorityQueue<Integer> larg

【论文复现】中值滤波改进：Noise Adaptive Fuzzy Switching Median Filter（NAFSMF）

Noise Adaptive Fuzzy Switching Median Filter (NAFSM) 将图像 X X X的噪声像素置0，非噪声像素置1，保存到binary noise mask N

2.10英文题面翻译

描述 Given a sequence of N nonnegative integers. Let's define the median of such sequence. If N is odd the median is the element with stands in the middle of the sequence after it is sorted. One may notice that in this case the median has position (N+1

题目翻译（23）

Sequence Median（http://noi.openjudge.cn/ch0401/1625/）描述 Given a sequence of N nonnegative integers. Let's define the median of such sequence. If N is odd the median is the element with stands in the middle of the sequence after it is sorted. One may

cf1144 E. Median String（思维）

题意：给定两个字符串 \(s1, s2\)，求区间 \([s1,s2]\) 中按字典序位于中间的串。思路：整数区间 \([l,r]\) 的中位数就是 \((l+r)/2\) 。现在要求字符串的中位数，就把字符串看成26进制数，模拟一下加法和竖式除以2即可。 cin >> n >> s1 >> s2; for(int i = n - 1; i >= 0; i--) {

pat甲级1029 Median

Given an increasing sequence S of N integers, the median is the number at the middle position. For example, the median of S1 = { 11, 12, 13, 14 } is 12, and the median of S2 = { 9, 10, 15, 16, 17 } is 15. The median of two sequences is defined to be the

4. Median of Two Sorted Arrays

这道题最简单的思路是把两个数组合并起来，再排序，如果数组长度是奇数，return 中间的那个数，如果数组长度是偶数，return 中间两个数的平均值。时间复杂度 O(nlogn)用于数组排序。 public double findMedianSortedArrays(int[] nums1, int[] nums2) { int[] nums = new int[

295. Find Median from Data Stream

当我拿到这道题的时候，第一时间想到的就是如下的暴力解法，时间复杂度：O(nlogn)+O(1)≃O(nlogn)，空间复杂度：O(n) class MedianFinder { private List<Integer> list = new ArrayList<>(); public MedianFinder() { } public void addNum(int num) {

O - Median Maximization

传送门未知题意：给两个整数n，s，寻找一个可能的中位数最大的元素非负的数组（元素可以相同），使得数组长度为n，各元素之和为s。中位数的定义见题目思路：既然是非负数组，就意味着可以有为0的元素。而且元素可以相同，就意味着可以将中位数前的数全部设为0，原题转换为寻找一个长度为n/2+1的递增

[LeetCode] 4. Median of Two Sorted Arrays（Python）

[LeetCode] 4. Median of Two Sorted Arrays（Python） 1. 题目2. 题目理解3. 代码实现 1. 题目 Given two sorted arrays nums1 and nums2 of size m and n respectively, return the median of the two sorted arrays. The overall run time complexity should be O(log

AT2163 [AGC006B] Median Pyramid Easy

洛谷题面题目大意给出一个 \(n\) 层的方格金字塔,自顶向下依次标号为第 \(1\) 到第 \(n\) 层。其中第 \(i(1\le i\le n)\) 层有 \(2i-1\) 个方格。第 \(n\) 层有一个 \(1\) 到 \(2n-1\) 的排列，其他层的数字按以下规则生成：方格 \(b\) 中填写的整数,是方格 \(b\) 正下方,左下方

ANNS-树方法

树方法目录树方法kd-tree kd-tree kd-tree (k dimensional tree )是树方法的经典算法，其是二分搜索树在多维空间的推广。二分搜索树检索迅速的原因是规定将数据中大于当前节点数据的方在一侧(比如右子树)，而不小于的放在另一侧(比如左子树),这样检索数据时，即可获得logn的速度。kd-t

AT3857-[AGC020C]Median Sum【背包,bitset】

正题题目链接:https://www.luogu.com.cn/problem/AT3857 题目大意给出\(n\)个数字的一个序列\(a\)，求它的所有非空子集的和的中位数。 \(1\leq n,a_i\leq 2000\) 解题思路考虑到假设所有数的和为\(S\)，一个集合的和为\(x\)，那么肯定有与其对应的另一个集合和为\(S-x\)。所以如

AT3857-[AGC020C]Median Sum【背包,bitset】

正题题目链接:https://www.luogu.com.cn/problem/AT3857 题目大意给出 n n n个数字的一个序列 a a

PAT-A1029 Median

A1029 Median Given an increasing sequence S of N integers, the median is the number at the middle position. For example, the median of S1 = { 11, 12, 13, 14 } is 12, and the median of S2 = { 9, 10, 15, 16, 17 } is 15. The median of two sequences is defin