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2022-2023年英语周报七年级第31期答案汇总
进入查看： 2022-2023年英语周报七年级第31期答案汇总 People might be surprised to see how today's Greenland looked during the last two inter glacial periods. During the Last Inter glacial, global sea levels increased by 15 to 30 feet, largelOil Deposits
链接： 题目： Problem Description The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous squareOil Deposits（dfs)
题目 The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square plots. It then analyzOil Deposits
Problem Description Input Output Sample Input 题意：'@'代表油袋，'*'代表没有油；油袋相连（水平，垂直，斜对角线相连）的表示一个油藏。问给你一个m*n大小的矩阵有多少个油藏？ 1.DFS #include<cstdio> #include<iostream> #include<algorithm> using namespace std; const int N=10UVA572 油田 Oil Deposits（BFS复习）
#include <iostream> #include <set> #include <vector> #include <cmath> #include <cstdio> #include <cstring> #include <algorithm> #include <queue> #define ll long long using namespace std; const int M = 1e3 +Oil Deposits
Oil Deposits Problem Description The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous油田问题
油田问题 Problem DescriptionInputOutputSample InputSample Output 问题翻译：DescriptionInputOutput Problem Description The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectOil Deposits 油藏
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 63433 Accepted Submission(s): 36432 Problem Description The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GOil Deposits 新年特辑篇
链接：E - Oil Deposits 题目： The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square pHDU 1241 Oil Deposits（经典DFS）
嗯... 题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=1241 很经典的一道dfs，但是注意每次查到一个@之后，都要把它变成“ * ”，然后继续dfs，这样在dfs过程中一些@变成了“ * ”。这样也不需要flag数组，当继续遍历图的时候，再有@就是独立的，ans++。最后ans里边便是答案... A搜索专题训练 E - Oil Deposits
题目 The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square plots. It then analyzesOil Deposits HDU - 1241
The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square plots. It then analyzes eA - Oil Deposits DFS
The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square plots. It then analyzes eacHDU 1241 Oil Deposits（DFS）
Oil Deposits 原题链接：HDU 1241 Problem Description The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the lUVA572 Oil Deposits DFS求解
小白书上经典DFS题目。 1. 递归实现 // from: https://www.cnblogs.com/huaszjh/p/4686092.html #include <stdio.h> #include <string.h> #define maxn 105 unsigned char data[maxn][maxn]; int m, n, vis[maxn][maxn]; void dfs(int x, int y, int ans) { if (x <HDU1241 Oil Deposits
题目： 小烤 同志负责探测lz地下石油储藏。 小烤现在在一块矩形区域探测石油。他们通过专业设备，来分析每个小块中是否蕴藏石油。如果这些蕴藏石油的小方格相邻（横向相邻，纵向相邻，还有对角相邻），那么他们被认为是同一油藏的一部分。在这块矩形区域，可能有很多油藏。你的任务是确定有多少不UVA 572 Oil Deposits
思路： // 题意：输入一个字符矩阵，统计字符@组成多少个四连块#include<cstdio>#include<cstring>const int maxn = 100 + 5;char pic[maxn][maxn];int m, n, idx[maxn][maxn];void dfs(int r, int c, int id) { if (r < 0 || r >= m || c < 0 || c >= n) return;题目--oil Deposits（油田） 基础DFS（深度搜索）
上一次基本了解了下BFS，这次又找了个基本的DFS题目来试试水，DFS举个例子来说就是 一种从树的最左端开始一直搜索到最底端，然后回到原端再搜索另一个位置到最底端，也就是称为深度搜索的DFS--depth first search，话不多说，直接上题了解： Description:某石油勘探公司正在按计划勘探地下油田UVA - 572_Oil Deposits（FloodFill）
要求：计算二维中连通块个数。 #include<bits/stdc++.h> using namespace std; const int maxn = 100 + 3; const int maxm = 100 + 3; int m, n; char buf[maxm][maxn]; bool book[maxm][maxn]; void floodfill(int r, int c) { book[r][c] = true; for(int dr = -1; dr