Bounded

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java~PECS原则

pecs 全称是Producer Extends Consumer Super 使用extends确定上界的只能是生产者，只能往外生产东西，取出的就是上界类型。不能往里塞东西。使用Super确定下界的只能做消费者，只能往里塞东西。取出的因为无法确定类型只能转成Object类型看代码更好理解。代码 List<? extends Numb

Minesweeper使用学习（1）

Minesweeper使用之BGP测试学习一、BGP1 1.导入BGP1的网络。 init-testrig /home/yahui/Desktop/batfish-abstraction-fixes/test_rigs/smt-examples/BGP1 这里路径是电脑上存网络配置文件的文件夹这个网络很小，只有两个路由器，大概长这样（这里R2的接口loopback0的ip我标错了

[Leetcode 1041]机器人围成圈 Robot Bounded In Circle

题目机器人从（0,0）出发，初始化向北三种指令 G当前方向+1步，L左转90度，R右转90度问指令结束后是否成圆圈（只有可能回原点时才成圈）返回true/false On an infinite plane, a robot initially stands at (0, 0) and faces north. The robot can receive one of three instructions: "

795. Number of Subarrays with Bounded Maximum

We are given an array nums of positive integers, and two positive integers left and right (left <= right). Return the number of (contiguous, non-empty) subarrays such that the value of the maximum array element in that subarray is at least left and at

[LeetCode] 1041. Robot Bounded In Circle

On an infinite plane, a robot initially stands at (0, 0) and faces north. The robot can receive one of three instructions: "G": go straight 1 unit; "L": turn 90 degrees to the left; "R": turn 90 degress to the right. The r

面向服务架构设计-note

常用方法：战略分治：抽象： DDD：一个具有有限的业务范围，可以帮助我们更更好的做服务化架构设计。DDD战略略建模中的限界上下⽂文(Bounded Context)，其核⼼心就是将特定职责的相关⾏行行为控制在⼀一个有限边界的范围内。战术

微服务架构 (七): 微服务粒度设计上的核心设计原则与思考的面向

架构师在设计微服务时, 需把握一个核心的设计原则:微服务 “外部的世界” 远比 “内部的世界” 重要。微服务外部与内部的世界是以微服务边界上下文 (Bounded Context) 作划分的。而微服务的接口; 例如: REST 接口; 便是拉通了微服务外部与内部的世界。微服务外部的世界包括:A.

1041. Robot Bounded In Circle

On an infinite plane, a robot initially stands at (0, 0) and faces north. The robot can receive one of three instructions: "G": go straight 1 unit; "L": turn 90 degrees to the left; "R": turn 90 degress to the right. The r

【leetcode】1041. Robot Bounded In Circle

题目如下： On an infinite plane, a robot initially stands at (0, 0) and faces north. The robot can receive one of three instructions: "G": go straight 1 unit; "L": turn 90 degrees to the left; "R": turn 90 degress to the right.

Leetcode-5055 Robot Bounded In Circle(困于环中的机器人)

1 #define _for(i,a,b) for(int i = (a);i < b;i ++) 2 int dx[] = {-1,0,1,0}; 3 int dy[] = {0,1,0,-1}; 4 class Solution 5 { 6 public: 7 bool isRobotBounded(string instructions) 8 { 9 int fang = 0;10 int x = 0,y

(5)How to let go of being a "good" person — and become a better person

https://www.ted.com/talks/dolly_chugh_how_to_let_go_of_being_a_good_person_and_become_a_better_person/transcript 00:13So a friend of mine was riding in a taxi to the airport the other day, and on the way, she was chatting with the taxi driver, and he said