LeetCode 1212. Team Scores in Football Tournament
作者:互联网
Table: Teams
+---------------+----------+ | Column Name | Type | +---------------+----------+ | team_id | int | | team_name | varchar | +---------------+----------+ team_id is the primary key of this table. Each row of this table represents a single football team.
Table: Matches
+---------------+---------+ | Column Name | Type | +---------------+---------+ | match_id | int | | host_team | int | | guest_team | int | | host_goals | int | | guest_goals | int | +---------------+---------+ match_id is the primary key of this table. Each row is a record of a finished match between two different teams. Teams host_team and guest_team are represented by their IDs in the teams table (team_id) and they scored host_goals and guest_goals goals respectively.
You would like to compute the scores of all teams after all matches. Points are awarded as follows:
- A team receives three points if they win a match (Score strictly more goals than the opponent team).
- A team receives one point if they draw a match (Same number of goals as the opponent team).
- A team receives no points if they lose a match (Score less goals than the opponent team).
Write an SQL query that selects the team_id, team_name and num_points of each team in the tournament after all described matches. Result table should be ordered by num_points (decreasing order). In case of a tie, order the records by team_id (increasing order).
The query result format is in the following example:
Teams table: +-----------+--------------+ | team_id | team_name | +-----------+--------------+ | 10 | Leetcode FC | | 20 | NewYork FC | | 30 | Atlanta FC | | 40 | Chicago FC | | 50 | Toronto FC | +-----------+--------------+ Matches table: +------------+--------------+---------------+-------------+--------------+ | match_id | host_team | guest_team | host_goals | guest_goals | +------------+--------------+---------------+-------------+--------------+ | 1 | 10 | 20 | 3 | 0 | | 2 | 30 | 10 | 2 | 2 | | 3 | 10 | 50 | 5 | 1 | | 4 | 20 | 30 | 1 | 0 | | 5 | 50 | 30 | 1 | 0 | +------------+--------------+---------------+-------------+--------------+ Result table: +------------+--------------+---------------+ | team_id | team_name | num_points | +------------+--------------+---------------+ | 10 | Leetcode FC | 7 | | 20 | NewYork FC | 3 | | 50 | Toronto FC | 3 | | 30 | Atlanta FC | 1 | | 40 | Chicago FC | 0 | +------------+--------------+---------------+
简要翻译:
两张表:队伍表和比赛表。统计队伍积分,胜3分,平1分,负0分,查询个队伍排名榜,查询结果先按积分降序,然后按team_id升序排列。
建表语句:
CREATE TABLE Teams ( team_id INT , team_name VARCHAR (20) ) ; CREATE TABLE Matches ( match_id INT , host_team INT , guest_team INT , host_goals INT, guest_goals INT ) ; INSERT INTO Teams (team_id, team_name) VALUES (10, 'Leetcode FC') ; INSERT INTO Teams (team_id, team_name) VALUES (20, 'NewYork FC') ; INSERT INTO Teams (team_id, team_name) VALUES (30, 'Atlanta FC') ; INSERT INTO Teams (team_id, team_name) VALUES (40, 'Chicago FC') ; INSERT INTO Teams (team_id, team_name) VALUES (50, 'Toronto FC') ; INSERT INTO Matches ( match_id, host_team, guest_team, host_goals, guest_goals ) VALUES (1, 10, 20, 3, 0) ; INSERT INTO Matches ( match_id, host_team, guest_team, host_goals, guest_goals ) VALUES (2, 30, 10, 2, 2) ; INSERT INTO Matches ( match_id, host_team, guest_team, host_goals, guest_goals ) VALUES (3, 10, 50, 5, 1) ; INSERT INTO Matches ( match_id, host_team, guest_team, host_goals, guest_goals ) VALUES (4, 20, 30, 1, 0) ; INSERT INTO Matches ( match_id, host_team, guest_team, host_goals, guest_goals ) VALUES (5, 50, 30, 1, 0) ;
SQL思路:
一、查询每场比赛各队伍得分:
# 作为主队的得分统计:
1 SELECT 2 team_id, 3 team_name, 4 IF( 5 host_goals > guest_goals, 6 3, 7 IF(host_goals = guest_goals, 1, 0) 8 ) AS points 9 FROM 10 teams, 11 matches 12 WHERE team_id = host_team;
#作为客队的得分统计
1 SELECT 2 team_id, 3 team_name, 4 IF( 5 host_goals > guest_goals, 6 0, 7 IF(host_goals = guest_goals, 1, 3) 8 ) AS points 9 FROM 10 teams, 11 matches 12 WHERE team_id = guest_team;
二、将上两张表union all ,然后分组聚合查询,然后发现少了没参赛队伍的积分。因此需要left join 。最终查询语句如下
1 SELECT 2 t.team_id, 3 t.team_name, 4 SUM(IFNULL(points,0)) AS num_points 5 FROM 6 teams t LEFT JOIN 7 ( 8 SELECT 9 team_id, 10 team_name, 11 IF( 12 host_goals > guest_goals, 13 3, 14 IF(host_goals = guest_goals, 1, 0) 15 ) AS points 16 FROM 17 teams, 18 matches 19 WHERE team_id = host_team 20 UNION ALL 21 SELECT 22 team_id, 23 team_name, 24 IF( 25 host_goals > guest_goals, 26 0, 27 IF(host_goals = guest_goals, 1, 3) 28 ) AS points 29 FROM 30 teams, 31 matches 32 WHERE team_id = guest_team 33 )temp ON 34 t.team_id = temp.team_id 35 GROUP BY team_id 36 ORDER BY num_points DESC ,team_id ASC ;
标签:1212,Tournament,guest,Football,host,goals,team,id,name 来源: https://www.cnblogs.com/onePunchCoder/p/11619433.html