其他分享
首页 > 其他分享> > 7段数码管绘制(尾号0,1)

7段数码管绘制(尾号0,1)

作者:互联网

代码如下:

import turtle as t
import time
def popspace():
t.penup()
t.fd(5)
def popline(draw):
popspace()
t.pendown() if draw else t.penup()
t.fd(40)
popspace()
t.right(90)
def popstart(d):
popline(True) if d in [2,3,4,5,6,8,9] else popline(False)
popline(True) if d in [0,1,3,4,5,6,7,8,9] else popline(False)
popline(True) if d in [0,2,3,5,6,8,9] else popline(False)
popline(True) if d in [0,2,6,8] else popline(False)
t.left(90)
popline(True) if d in [0,4,5,6,8,9] else popline(False)
popline(True) if d in [0,2,3,5,6,7,8,9] else popline(False)
popline(True) if d in [0,1,2,3,4,7,8,9] else popline(False)
t.left(180)
t.penup()
t.fd(30)
def popdate(date):
t.pencolor((1,0.36,0.28))
t.speed(9)
for i in date:
if i == '-':
t.write('年',font=("Arial", 30, "normal"))
t.pencolor((0.93,0.51,0.93))
t.fd(60)
elif i == '=':
t.write('月',font=("Arial", 30, "normal"))
t.pencolor((0.5,0.5,0))
t.fd(60)
elif i == '+':
t.write('日',font=("Arial", 30, "normal"))
t.pencolor((0.25,0.88,0.82))
t.fd(40)
#换行输出
t.seth(-90)
t.fd(100)
t.seth(180)
t.fd(700)
t.seth(-90)
t.fd(40)
t.seth(0)
t.fd(40)
elif i == '*':
t.write('时',font=("Arial", 30, "normal"))
t.pencolor((0.18,0.55,0.34))
t.fd(60)
else:
popstart(eval(i))
def main():
t.setup(1000, 800, None,None)
t.penup()
t.fd(-350)
t.pensize(6)
popdate(time.strftime('%Y-%m=%d+%H*/',time.localtime()))
t.hideturtle()
main()

运行结果如下:

 

 昵称:Binnie

学号:2020310143041

标签:popline,False,True,30,else,数码管,fd,尾号,绘制
来源: https://www.cnblogs.com/Binnie/p/15449968.html