Chauchy-Schwarze不等式
作者:互联网
设f(x)和g(x)都在[a,b]上可积,则
$[∫_a^bf(x)g(x)dx]^2≤∫_a^bf^2(x)dx∫_a^bg^2(x)dx$
证明;对于任意的实数t,显然\([tf(x)+g(x)]^2在[a,b]上可积,且tf(x)+g(x)]^2≥0\),则
$[∫_a^b[tf(x)+g(x)]^dx2≥0$
即
$t^2∫_a^bf^2(x)dx+2t∫_a^bf(x)g(x)dx+∫_a^bg^2(x)dx≥0 $
则
$Δ=[2∫_a^bf(x)g(x)dx]^2-4∫_a^bf^2(x)dx∫_a^bg^2(x)dx≤0$
即
$[∫_a^bf(x)g(x)dx]^2≤∫_a^bf^2(x)dx∫_a^bg^2(x)dx$
标签:可积,2t,bf,bg,不等式,Chauchy,dx,tf,Schwarze 来源: https://www.cnblogs.com/valar-morghulis/p/14847504.html