2个线程交替输出A1B2C3问题
作者:互联网
引言
经典多线程编程面试题
使用两个线程交替输出A1B2C3......Z26
实现方案1
public static void method2() throws InterruptedException {
Object object = new Object();
AtomicInteger atomicInteger = new AtomicInteger(0);
new Thread(() -> {
int i = 0;
while (i < 26) {
synchronized (object) {
if (atomicInteger.get() % 2 == 0) {
atomicInteger.incrementAndGet();
System.out.print((char) (i++ + 'A'));
} else {
Thread.yield();
}
}
}
}).start();
new Thread(() -> {
int i = 0;
while (i < 26) {
synchronized (object) {
if (atomicInteger.get() % 2 != 0) {
atomicInteger.incrementAndGet();
System.out.print(++i);
} else {
Thread.yield();
}
}
}
}).start();
}
实现方案2
存在一定问题,有可能输出 1A2B3C
public void method1() {
Object object = new Object();
Thread t1 = new Thread(() -> {
synchronized (object) {
for (int i = 1; i <= 26; i++) {
System.out.print(String.valueOf((char) ('A' + i - 1)));
object.notify();
try {
object.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
});
Thread t2 = new Thread(() -> {
synchronized (object) {
for (int i = 1; i <= 26; i++) {
System.out.print(i);
object.notify();
try {
object.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
});
t1.start();
t2.start();
}
若存在问题,欢迎大家指出
标签:synchronized,Thread,int,object,A1B2C3,交替,线程,atomicInteger,new 来源: https://www.cnblogs.com/yanchuanbin/p/14796995.html