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死锁与递归锁

作者:互联网


from threading import Thread,Lock import time mutexA=Lock() mutexB=Lock() class MyThread(Thread): def run(self): self.func1() self.func2() def func1(self): mutexA.acquire() print('\033[41m%s 拿到A锁\033[0m' %self.name) mutexB.acquire() print('\033[42m%s 拿到B锁\033[0m' %self.name) mutexB.release() mutexA.release() def func2(self): mutexB.acquire() print('\033[43m%s 拿到B锁\033[0m' %self.name) time.sleep(2) mutexA.acquire() print('\033[44m%s 拿到A锁\033[0m' %self.name) mutexA.release() mutexB.release() if __name__ == '__main__': for i in range(10): t=MyThread() t.start()

  死锁↑    递归锁↓

from threading import Lock,Thread,RLock
import time
mutexB=mutexA=RLock()       #同一把锁锁
class MyThread(Thread):
    def run(self):
        self.f1()
        self.f2()
    def f1(self):
        mutexA.acquire()
        print('拿到A锁',self.name)
        mutexB.acquire()
        print('拿到B锁',self.name)
        mutexB.release()
        mutexA.release()
    def f2(self):
        mutexB.acquire()
        print('拿到B锁', self.name)
        mutexA.acquire()
        print('拿到A锁', self.name)
        mutexA.release()
        mutexB.release()
if __name__ == '__main__':
    for i in range(10):
        t = MyThread()
        t.start()

  

标签:__,name,递归,self,死锁,mutexA,mutexB,033
来源: https://blog.51cto.com/52770825/2795064