PAT乙级1019
作者:互联网
特殊判断点2、1000等。
注意设置字符串0的补全就问题不大,这里利用了fill这个函数。
#include <iostream>
#include <stdlib.h>
#include <string>
#include <string.h>
using namespace std;
int jiangxp(string s);
int shengxp(string s);
string fill(string s);
int m, n,p,q;
int i = 0;
int j = 0;
char tmp;
int sum = 0;
bool panduan = false;
int main()
{
//i是非递增,j是非递减
string s;
cin >> s;
s = fill(s);
for (i = 0; i < s.length(); i++)
{
for (j = i + 1; j < s.length();j++)
{
if (s[i] != s[j])
panduan = true;
}
}
if (panduan == false)
{
p = atoi(s.c_str());
printf("%04d - %04d = %04d",p,p,p-p);
}
else
{
while (true)
{
s = fill(s);
i = jiangxp(s);
j = shengxp(s);
sum = i - j;
printf("%04d - %04d = %04d\n",i,j,sum);
s = to_string(sum);
if (sum == 6174)
break;
}
}
return 0;
}
int jiangxp(string s)
{
for (m = 0; m < s.length(); m++)
{
for (n = m + 1; n < s.length(); n++)
{
if (s[n] > s[m])
{
tmp = s[n];
s[n] = s[m];
s[m] = tmp;
}
}
}
i = atoi(s.c_str());
return i;
}
int shengxp(string s)
{
for (m = 0; m < s.length(); m++)
{
for (n = m + 1; n < s.length(); n++)
{
if (s[n] < s[m])
{
tmp = s[n];
s[n] = s[m];
s[m] = tmp;
}
}
}
j = atoi(s.c_str());
return j;
}
string fill(string s)
{
while (s.length() < 4)
{
s = s + '0';
}
return s;
}
标签:tmp,PAT,string,int,04d,乙级,++,length,1019 来源: https://blog.csdn.net/taitoushuxingx/article/details/116353034