leetcode 116 填充每个节点的下一个右侧节点指针

/*
// Definition for a Node.
class Node {
public:
    int val;
    Node* left;
    Node* right;
    Node* next;

    Node() : val(0), left(NULL), right(NULL), next(NULL) {}

    Node(int _val) : val(_val), left(NULL), right(NULL), next(NULL) {}

    Node(int _val, Node* _left, Node* _right, Node* _next)
        : val(_val), left(_left), right(_right), next(_next) {}
};
*/

class Solution {
public:
    Node* connect(Node* root) {
        if(!root)
        {
            return 0;
        }
        Node* Left=connect(root->left);
        Node* Right=connect(root->right);
    //子树之间的连线
        if(Left && Right)
        {
            while(Left && Right)
            {
                Left->next=Right;
                Left=Left->right;
                Right=Right->left;
            }
             while(Right)
            {
                Right->next=NULL;
                Right=Right->right;
            }
            root->next=NULL;
            return root;
        }
        else if(!Left && Right)
        {
            while(Right)
            {
                Right->next=NULL;
                Right=Right->right;
            }
            root->next=NULL;
            return root;
        }
        else if(!Right && Left)
        {
            while(Left)
            {
                Left->next=NULL;
                Left=Left->right;
            }
            root->next=NULL;
            return root;
        }
        else{
            root->next=NULL;
            return root;
        }
    }
};

标签：Node,Right,leetcode,next,116,NULL,root,节点,Left
来源： https://www.cnblogs.com/libin123/p/14598884.html