lua 实现数字转换千分法描述的字符串

话不多说，直接上代码。

-- 如 1234567 转换为 1,234,567
---@param number   数字
---@param decimalCount  需要保留小数点后的位数
function thousandNum(number, decimalCount)
	if type(number) ~= "number" then
		return number;
	end

	if number == math.huge then
		return tostring(number);
	end

	local intNum = number;
	local floatStr = "";

	--如果是小数，需要保留小数点后的数字
	local arr = stringExplode(tostring(number), ".");
	if Utils.sizeof(arr) > 1 then
		intNum = tonumber(arr[1]);    --整数部分
		floatStr = arr[2];			  --小数部分
	end

	if decimalCount and decimalCount > 0 then
		floatStr = string.sub(floatStr, 1, decimalCount);
		if sizeof(floatStr) < decimalCount then
			-- 小数部位位数不足的，用0补足
			for i = 1, decimalCount - sizeof(floatStr) do
				floatStr = floatStr .. "0" ;
			end
		end
	end

	local ret;

	repeat
		local num , _ =  math.modf(intNum % 1000);
		intNum = (intNum - num) / 1000;
		local str =  tostring(num)
		if intNum <= 0 then
			str = tostring(num);
		end

		if ret then
			ret = str .. "," .. ret;
		else
			ret = str;
		end

	until intNum <= 0;

	if Utils.sizeof(floatStr) > 0 then
		ret = string.format("%s.%s", ret, floatStr);
	end
	return ret;
end
---@param t table or string 
function sizeof(t)
	local n = 0;
	if type(t) == "table" then
		-- 遍历 table，累加元素个数
		for __, __ in pairs(t) do
			n = n + 1;
		end
	elseif type(t) == "string" then
		n = string.len(t);
	end

	return n;
end

-- 将字符串打断
function stringExplode(str, sep)
	if sep == nil then
		sep = "%s"
	end
	local t = {};
	local i = 1;
	for str in string.gmatch(str, "([^"..sep.."]+)") do
		t[i] = str;
		i = i + 1;
	end
	return t;
end

标签：end,floatStr,--,千分,number,lua,decimalCount,字符串,local
来源： https://blog.csdn.net/qq_37659181/article/details/114896957