Leetcode 705. Design HashSet
作者:互联网
文章作者:Tyan
博客:noahsnail.com | CSDN | 简书
1. Description
2. Solution
- Version 1
class MyHashSet:
def __init__(self):
self.hashset = []
def add(self, key: int) -> None:
if key not in self.hashset:
self.hashset.append(key)
def remove(self, key: int) -> None:
if key in self.hashset:
self.hashset.remove(key)
def contains(self, key: int) -> bool:
if key in self.hashset:
return True
return False
- Version 2
class MyHashSet:
def __init__(self):
self.hashset = [False] * 1000001
def add(self, key: int) -> None:
self.hashset[key] = True
def remove(self, key: int) -> None:
self.hashset[key] = False
def contains(self, key: int) -> bool:
return self.hashset[key]
- Version 3
class MyHashSet:
def __init__(self):
self.hashset = [[] for _ in range(1000)]
def add(self, key: int) -> None:
index = self.hash(key)
if key not in self.hashset[index]:
self.hashset[index].append(key)
def remove(self, key: int) -> None:
index = self.hash(key)
if key in self.hashset[index]:
self.hashset[index].remove(key)
def contains(self, key: int) -> bool:
index = self.hash(key)
return key in self.hashset[index]
def hash(self, key):
return key % 1000
Reference
标签:index,hashset,int,705,self,Design,key,Leetcode,def 来源: https://blog.csdn.net/Quincuntial/article/details/114008384