其他分享
首页 > 其他分享> > [AGC012E] Camel and Oases

[AGC012E] Camel and Oases

作者:互联网

#include <bits/stdc++.h>
const int N=200005;
int n,v,a[N],dl[N][20],dr[N][20],pre[1<<20],suf[1<<20],dp[N],W;
int main(){
	scanf("%d%d",&n,&v);
	for (int i=1;i<=n;i++) scanf("%d",&a[i]);
	W=0;
	while (v>>W) W++;
	W++;
	for (int i=0;i<W;i++) dl[1][i]=1,dr[n][i]=n,dr[n+1][i]=n,dl[0][i]=1;
	for (int i=2;i<=n;i++)
		for (int k=0;k<W;k++)
			if (a[i]-a[i-1]<=(v>>k)) dl[i][k]=dl[i-1][k];
			else dl[i][k]=i;
	for (int i=n-1;i>=1;i--)
		for (int k=0;k<W;k++)
			if (a[i+1]-a[i]<=(v>>k)) dr[i][k]=dr[i+1][k];
			else dr[i][k]=i;
	for (int i=0;i<(1<<W);i++)
		for (int k=0;k<W;k++){
			if (i&(1<<k)) continue;
			pre[i|(1<<k)]=std::max(pre[i|(1<<k)],dr[pre[i]+1][k]);
		}
	for (int i=0;i<(1<<W);i++) suf[i]=n+1;
	for (int i=0;i<(1<<W);i++)
		for (int k=0;k<W;k++){
			if (i&(1<<k)) continue;
			suf[i|(1<<k)]=std::min(suf[i|(1<<k)],dl[suf[i]-1][k]);
		}
	int all=(1<<W)-1-1;
	memset(dp,0x3f,sizeof(dp));
	for (int i=0;i<(1<<W);i+=2)
		dp[pre[i]]=std::min(dp[pre[i]],suf[all^i]);
	for (int i=n;i>=0;i--) dp[i]=std::min(dp[i],dp[i+1]); 
	for (int i=1;i<=n;i++){
		if (dp[dl[i][0]-1]<=dr[i][0]+1) puts("Possible");
		else puts("Impossible");
	}
}

标签:AGC012E,Camel,int,dl,else,--,Oases,dr,dp
来源: https://www.cnblogs.com/flyfeather6/p/14380971.html