WERTYU

poj2538

题目

Problem Description
A common typing error is to place the hands on the keyboard one row to the right of the correct position. So "Q" is typed as "W" and "J" is typed as "K" and so on. You are to decode a message typed in this manner. Input Input consists of several lines of text. Each line may contain digits, spaces, upper case letters (except Q, A, Z), or punctuation shown above [except back-quote (`)]. Keys labelled with words [Tab, BackSp, Control, etc.] are not represented in the input. Output You are to replace each letter or punctuation symbol by the one immediately to its left on the QWERTY keyboard shown above. Spaces in the input should be echoed in the output. Sample Input

O S, GOMR YPFSU/

Sample Output

Yes
I AM FINE TODAY.

题目大意：

常见的键入错误是将手放在键盘上，将手放在正确位置右侧的一行。因此，"Q"被键入为"W"，"J"被键入为"K"，等等。即输出键入字符前的那个字符。

输入中不表示标有单词 [Tab、BackSp、控件等] 的键。

输入中的空格应在输出中回显。

解题思路

将键盘上的字符按键盘顺序存储为字符串s，输入一个字符c，遍历字符串s直至s[i]与c字符相等，输出s[i-1]。

代码

#include <iostream>
#include <algorithm>
#include <cstdio>
#include <cstring>
#include <cmath>
using namespace std;

int main()
{
    int c;
    char s[] = "`1234567890-=QWERTYUIOP[]\ASDFGHJKL;'ZXCVBNM,./"; //定义常量数组时无需指明大小
    while((c=getchar())!=EOF)
    {
        int i;
        for(i=0;s[i]&&s[i] != c; i++);
            if(s[i]) putchar(s[i-1]);
            else putchar(c);
    }
    return 0;
}

标签：字符,int,typed,键入,WERTYU,poj2538,Input,include
来源： https://www.cnblogs.com/Jernewson/p/14293589.html