1083 List Grades (25point(s))
作者:互联网
1083 List Grades (25point(s))
Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.
Input Specification:
Each input file contains one test case. Each case is given in the following format:
N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
… …
name[N] ID[N] grade[N]
grade1 grade2
where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade’s interval. It is guaranteed that all the grades are distinct.
Output Specification:
For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student’s name and ID, separated by one space. If there is no student’s grade in that interval, output NONE instead.
Sample Input 1:
4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100
Sample Output 1:
Mike CS991301
Mary EE990830
Joe Math990112
Sample Input 2:
2
Jean AA980920 60
Ann CS01 80
90 95
Sample Output 2:
NONE
#include<bits/stdc++.h>
using namespace std;
struct student{
string name,id;
int grade;
}stu[1000];
bool cmp(student s1,student s2){
return s1.grade>s2.grade;
}
int main(){
int n,grade1,grade2;
cin>>n;
for(int i=0;i<n;++i){
cin>>stu[i].name>>stu[i].id>>stu[i].grade;
}
cin>>grade1>>grade2;
int count=0;
vector<student> v;
for(int i=0;i<n;++i)
if(grade1<=stu[i].grade&&stu[i].grade<=grade2)
v.push_back(stu[i]);
sort(v.begin(),v.end(),cmp);
if(v.empty())
cout<<"NONE"<<endl;
else{
for(int i=0;i<v.size();++i){
cout<<v[i].name<<" "<<v[i].id<<endl;
}
}
}
标签:grade1,name,grade,List,25point,int,Grades,student,ID 来源: https://blog.csdn.net/weixin_44970602/article/details/111397007