go中如果想要实现别人写的接口,如何保证确实实现了那个接口而不是错过了什么?

在类型的实现方法上定义通用代码指令

var _ 要实现的接口  = (receiver类型)(nil)

比如要定义一个web处理程序

type  handler_def struct{}

var _ http.Handler = (*handler_def)(nil)

func (h *handler_def)ServeHTTP(参数){}

当你编译go build xxxx.go

报错参考如下,可以看到很清楚的解释.

# command-line-arguments
.\main.go:9:5: cannot use (*Handler)(nil) (type *Handler) as type http.Handler in assignment:
        *Handler does not implement http.Handler (wrong type for ServeHTTP method)
                have ServeHTTP(http.ResponseWriter, http.Request)
                want ServeHTTP(http.ResponseWriter, *http.Request)

标签：ServeHTTP,http,nil,实现,接口,Handler,go,type
来源： https://www.cnblogs.com/keystone/p/14010693.html