集合:map接口及其实现类(HashMap、TreeMap)
作者:互联网
1、map接口
(1)特点
不能包含重复的键,但是值可以有重复
一个key只能映射一个值
用于保存一组键值对的映射
(2)方法
- put(键,值):添加,要注意list接口的添加是add方法,该键不存在就添加,存在的话就覆盖
- remove(键):删
- containsKey(键):判断键是否存在
- containsValue(值):判断值是否存在
- get(键):根据键获取值
2、Map接口的常用方法
(1)添加
put:
@Test public void test1() { Map map=new HashMap(); map.put("4","zhai"); map.put("2","liu"); map.put("9","zhang"); map.put("1","zhao"); map.put("6","ma"); map.put("7","sun"); map.put("123",null); map.put(null,"qqq"); System.out.println(map); }
(2)删除
remove:
@Test public void test1() { Map map=new HashMap(); map.put("4","zhai"); map.put("2","liu"); map.put("9","zhang"); map.put("1","zhao"); map.put("6","ma"); System.out.println(map); map.remove("4"); System.out.println(map); }
{1=zhao, 2=liu, 4=zhai, 6=ma, 9=zhang} {1=zhao, 2=liu, 6=ma, 9=zhang}
(3)获取
get:
@Test public void test1() { Map map=new HashMap(); map.put("4","zhai"); map.put("2","liu"); map.put("9","zhang"); map.put("1","zhao"); map.put("6","ma"); System.out.println(map.get("6")); }
ma
containsKey:键是否存在
@Test public void test1() { Map map=new HashMap(); map.put("4","zhai"); map.put("2","liu"); map.put("9","zhang"); map.put("1","zhao"); map.put("6","ma"); System.out.println(map.containsKey("6")); System.out.println(map.containsKey("123")); }
true false
containsValue:值是否存在
@Test public void test1() { Map map=new HashMap(); map.put("4","zhai"); map.put("2","liu"); map.put("9","zhang"); map.put("1","zhao"); map.put("6","ma"); System.out.println(map.containsValue("6")); System.out.println(map.containsValue("ma")); }
false true
集合大小:
@Test public void test1() { Map map=new HashMap(); map.put("4","zhai"); map.put("2","liu"); map.put("9","zhang"); map.put("1","zhao"); map.put("6","ma"); System.out.println(map.size()); }
5
是否为空:
@Test public void test1() { Map map=new HashMap(); map.put("4","zhai"); map.put("2","liu"); map.put("9","zhang"); map.put("1","zhao"); map.put("6","ma"); System.out.println(map.isEmpty()); }
false
通过size方法和isEmpty方法判断集合是否为空的效率是一样的
3、Map接口的遍历方式
(1)entrySet方式
@Test public void test1() { Map map=new HashMap(); map.put("4","zhai"); map.put("2","liu"); map.put("9","zhang"); map.put("1","zhao"); map.put("6","ma"); //获取所有的关系 Set entrys=map.entrySet(); Iterator iterator=entrys.iterator();//遍历 while (iterator.hasNext()){//获取每一对关系 Map.Entry entry= (Map.Entry) iterator.next(); System.out.println(entry); System.out.println(entry.getKey()+":"+entry.getValue()); } }
1=zhao 1:zhao 2=liu 2:liu 4=zhai 4:zhai 6=ma 6:ma 9=zhang 9:zhang
通过迭代器和增强for是一样的
(2)keySet方式
@Test public void test1() { Map map=new HashMap(); map.put("4","zhai"); map.put("2","liu"); map.put("9","zhang"); map.put("1","zhao"); map.put("6","ma"); //获取所有的键 Set keys=map.entrySet(); for (Object key:keys){ System.out.println(key); } }
1=zhao 2=liu 4=zhai 6=ma 9=zhang
以上两种方式不管是获取到所有的关系还是获取到所有的键,都只能用set来存储,因为只有set是不允许有重复的
4、HashMap
(1)底层原理:https://www.cnblogs.com/zhai1997/p/12677798.html
(2)源码分析:https://www.cnblogs.com/zhai1997/p/13028001.html
5、HashMap与HashTable
底层结构
HashMap:哈希表
HashTable:哈希表
版本
HashMap:1.2
HashTable:1.0
线程安全
HashMap:不安全
HashTable:安全
允许null键null值
HashMap:允许
HashTable:不允许
6、TreeMap
(1)特点
基于红黑树
根据键排序(如果键是自定义的类型则要像TreeSet那样手动添加比较器)
标签:map,ma,HashMap,zhang,TreeMap,zhao,put 来源: https://www.cnblogs.com/zhai1997/p/13449690.html