1131. 绝对值表达式的最大值
作者:互联网
给你两个长度相等的整数数组,返回下面表达式的最大值:
|arr1[i] - arr1[j]| + |arr2[i] - arr2[j]| + |i - j|
其中下标 i,j 满足 0 <= i, j < arr1.length。
示例 1:
输入:arr1 = [1,2,3,4], arr2 = [-1,4,5,6]
输出:13
示例 2:
输入:arr1 = [1,-2,-5,0,10], arr2 = [0,-2,-1,-7,-4]
输出:20
提示:
2 <= arr1.length == arr2.length <= 40000
-10^6 <= arr1[i], arr2[i] <= 10^6
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/maximum-of-absolute-value-expression
其实就是三维曼哈顿距离求最大
class Solution: def maxAbsValExpr(self, arr1: List[int], arr2: List[int]) -> int: fuhao=[1,-1] n=len(arr1) dists=[] for a in fuhao: for b in fuhao: for c in fuhao: maxDist=float('-inf') minDist=float('inf') for i in range(n): dist=arr1[i]*a+arr2[i]*b+i*c maxDist=max(maxDist,dist) minDist=min(minDist,dist) dists.append(maxDist-minDist) return max(dists)
标签:maxDist,dist,fuhao,1131,minDist,arr2,arr1,最大值,绝对值 来源: https://www.cnblogs.com/xxxsans/p/13372649.html