[CrackMe]160个CrackMe之19

[CrackMe]160个CrackMe之19

该代码难度很低，直接IDA F5 就可以计算出来

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#include<windows.h>
#include <iostream>

using namespace std;


int main() {
    char name[20];
    cout << "name:";
    cin >> name;
    unsigned int  v22 = strlen(name);
    unsigned int  v25 = 0x81276345;
    for (int i = 0; i < v22; ++i)
    {
        char v2 = name[i];
        v25 += v2;
        v25 ^= i << 8;
        v25 *= ~(i * v22) * (i + 1);
    }
    cout << "key:" << v25 << endl;
}

标签：name,v25,19,unsigned,char,int,CrackMe,160
来源： https://www.cnblogs.com/onetrainee/p/12870216.html