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P4097 [HEOI2013]Segment [李超树]

作者:互联网

李超树模板,细节有点多。。

// powered by c++11
// by Isaunoya
#include <bits/stdc++.h>

#define rep(i, x, y) for (register int i = (x); i <= (y); ++i)
#define Rep(i, x, y) for (register int i = (x); i >= (y); --i)

using namespace std;
using db = double;
using ll = long long;
using uint = unsigned int;
using ull = unsigned long long;

#define pii pair<int, int>
#define fir first
#define sec second

template <class T>

void cmax(T& x, const T& y) {
  if (x < y) x = y;
}

template <class T>

void cmin(T& x, const T& y) {
  if (x > y) x = y;
}

#define all(v) v.begin(), v.end()
#define sz(v) ((int)v.size())
#define pb emplace_back

template <class T>

void sort(vector<T>& v) {
  sort(all(v));
}

template <class T>

void reverse(vector<T>& v) {
  reverse(all(v));
}

template <class T>

void unique(vector<T>& v) {
  sort(all(v)), v.erase(unique(all(v)), v.end());
}

void reverse(string& s) { reverse(s.begin(), s.end()); }

const int io_size = 1 << 23 | 233;
const int io_limit = 1 << 22;
struct io_in {
  char ch;
#ifndef __WIN64
  char getchar() {
    static char buf[io_size], *p1 = buf, *p2 = buf;

    return (p1 == p2) && (p2 = (p1 = buf) + fread(buf, 1, io_size, stdin), p1 == p2) ? EOF : *p1++;
  }
#endif
  io_in& operator>>(char& c) {
    for (c = getchar(); isspace(c); c = getchar())
      ;

    return *this;
  }
  io_in& operator>>(string& s) {
    for (s.clear(); isspace(ch = getchar());)
      ;

    if (!~ch) return *this;

    for (s = ch; !isspace(ch = getchar()) && ~ch; s += ch)
      ;

    return *this;
  }

  io_in& operator>>(char* str) {
    char* cur = str;
    while (*cur) *cur++ = 0;

    for (cur = str; isspace(ch = getchar());)
      ;
    if (!~ch) return *this;

    for (*cur = ch; !isspace(ch = getchar()) && ~ch; *++cur = ch)
      ;

    return *++cur = 0, *this;
  }

  template <class T>

  void read(T& x) {
    bool f = 0;
    while ((ch = getchar()) < 48 && ~ch) f ^= (ch == 45);

    x = ~ch ? (ch ^ 48) : 0;
    while ((ch = getchar()) > 47) x = x * 10 + (ch ^ 48);
    x = f ? -x : x;
  }

  io_in& operator>>(int& x) { return read(x), *this; }

  io_in& operator>>(ll& x) { return read(x), *this; }

  io_in& operator>>(uint& x) { return read(x), *this; }

  io_in& operator>>(ull& x) { return read(x), *this; }

  io_in& operator>>(db& x) {
    read(x);
    bool f = x < 0;
    x = f ? -x : x;
    if (ch ^ '.') return *this;

    double d = 0.1;
    while ((ch = getchar()) > 47) x += d * (ch ^ 48), d *= .1;
    return x = f ? -x : x, *this;
  }
} in;

struct io_out {
  char buf[io_size], *s = buf;
  int pw[233], st[233];

  io_out() {
    set(7);
    rep(i, pw[0] = 1, 9) pw[i] = pw[i - 1] * 10;
  }

  ~io_out() { flush(); }

  void io_chk() {
    if (s - buf > io_limit) flush();
  }

  void flush() { fwrite(buf, 1, s - buf, stdout), fflush(stdout), s = buf; }

  io_out& operator<<(char c) { return *s++ = c, *this; }

  io_out& operator<<(string str) {
    for (char c : str) *s++ = c;
    return io_chk(), *this;
  }

  io_out& operator<<(char* str) {
    char* cur = str;
    while (*cur) *s++ = *cur++;
    return io_chk(), *this;
  }

  template <class T>

  void write(T x) {
    if (x < 0) *s++ = '-', x = -x;

    do {
      st[++st[0]] = x % 10, x /= 10;
    } while (x);

    while (st[0]) *s++ = st[st[0]--] ^ 48;
  }

  io_out& operator<<(int x) { return write(x), io_chk(), *this; }

  io_out& operator<<(ll x) { return write(x), io_chk(), *this; }

  io_out& operator<<(uint x) { return write(x), io_chk(), *this; }

  io_out& operator<<(ull x) { return write(x), io_chk(), *this; }

  int len, lft, rig;

  void set(int _length) { len = _length; }

  io_out& operator<<(db x) {
    bool f = x < 0;
    x = f ? -x : x, lft = x, rig = 1. * (x - lft) * pw[len];
    return write(f ? -lft : lft), *s++ = '.', write(rig), io_chk(), *this;
  }
} out;
#define int long long

template <int sz, int mod>

struct math_t {
  math_t() {
    fac.resize(sz + 1), ifac.resize(sz + 1);
    rep(i, fac[0] = 1, sz) fac[i] = fac[i - 1] * i % mod;

    ifac[sz] = inv(fac[sz]);
    Rep(i, sz - 1, 0) ifac[i] = ifac[i + 1] * (i + 1) % mod;
  }

  vector<int> fac, ifac;

  int qpow(int x, int y) {
    int ans = 1;
    for (; y; y >>= 1, x = x * x % mod)
      if (y & 1) ans = ans * x % mod;
    return ans;
  }

  int inv(int x) { return qpow(x, mod - 2); }

  int C(int n, int m) {
    if (n < 0 || m < 0 || n < m) return 0;
    return fac[n] * ifac[m] % mod * ifac[n - m] % mod;
  }
};

int gcd(int x, int y) { return !y ? x : gcd(y, x % y); }
int lcm(int x, int y) { return x * y / gcd(x, y); }

int n, m, ans;
const int maxn = 1e5 + 51;
const double eps = 1e-8;

int a[maxn], f[maxn];
struct Line {
  double k, b;
  inline double val(double x) { return k * x + b; }
} s[maxn];

struct SMT {
  int f[maxn << 2];

  void mdf(int ql, int qr, int l, int r, int p, int x) {
    int mid = l + r >> 1;
    if (ql <= l && r <= qr) {
      int y = f[p];
      if (y == 0) {
        f[p] = x;
        return;
      }
      double lx, ly, rx, ry;
      lx = s[x].val(l), rx = s[x].val(r);
      ly = s[y].val(l), ry = s[y].val(r);
      if (abs(lx - ly) <= eps && abs(rx - ry) <= eps) {
        f[p] = min(x, y);
        return;
      }
      if (lx <= ly && rx <= ry) {
        return;
      }
      if (lx >= ly && rx >= ry) {
        f[p] = x;
        return;
      }
      double midx = s[x].val(mid), midy = s[y].val(mid);
      if (abs(midx - midy) <= eps) {
        f[p] = min(x, y), x = max(x, y);
      } else if (midx >= midy) {
        f[p] = x, x = y, swap(lx, ly), swap(rx, ry);
      }
      if (lx >= ly)
        mdf(ql, qr, l, mid, p << 1, x);
      else
        mdf(ql, qr, mid + 1, r, p << 1 | 1, x);
      return;
    }
    if (ql <= mid) mdf(ql, qr, l, mid, p << 1, x);
    if (qr > mid) mdf(ql, qr, mid + 1, r, p << 1 | 1, x);
  }

  int qry(int p, int l, int r, int pos) {
    if (l == r) return f[p];
    int mid = l + r >> 1;
    int x, y = f[p];
    if (pos <= mid)
      x = qry(p << 1, l, mid, pos);
    else
      x = qry(p << 1 | 1, mid + 1, r, pos);
    if (x == 0 || y == 0) return x + y;
    double valx = s[x].val(pos);
    double valy = s[y].val(pos);
    if (abs(valx - valy) <= eps) {
      return min(x, y);
    }
    return (valx >= valy) ? x : y;
  }
} smt;

signed main() {
  // code begin.
  memset(a, 128, sizeof(a));
  n = 1;
  in >> m;
  while (m--) {
    int op;
    in >> op;
    if (op == 1) {
      int sx, sy, tx, ty;
      in >> sx >> sy >> tx >> ty;
      sx = (sx + ans - 1) % 39989;
      sy = (sy + ans - 1) % 1000000000;
      tx = (tx + ans - 1) % 39989;
      ty = (ty + ans - 1) % 1000000000;
      if (sx == tx) {
        if (a[sx] < max(sy, ty)) {
          a[sx] = max(sy, ty), f[sx] = n;
        }
      } else {
        if (sx > tx) {
          sx ^= tx ^= sx ^= tx, sy ^= ty ^= sy ^= ty;
        }
        s[n].k = 1.0 * (ty - sy) / (tx - sx);
        s[n].b = sy - s[n].k * sx;
        smt.mdf(sx, tx, 0, 4e4, 1, n);
      }
      ++n;
    } else {
      int x;
      in >> x;
      x = (x + ans - 1) % 39989;
      ans = smt.qry(1, 0, 4e4, x);
      if (ans == 0) {
        ans = f[x];
      } else if (abs(s[ans].val(x) - a[x]) <= eps) {
        ans = min(ans, f[x]);
      } else {
        ans = s[ans].val(x) >= a[x] ? ans : f[x];
      }
      out << ans << '\n';
    }
  }
  return 0;
  // code end.
}

标签:ch,return,int,sx,HEOI2013,P4097,io,ans,Segment
来源: https://www.cnblogs.com/Isaunoya/p/12820281.html