1155 Heap Paths (30分)
作者:互联网
One thing for sure is that all the keys along any path from the root to a leaf in a max/min heap must be in non-increasing/non-decreasing order.
Your job is to check every path in a given complete binary tree, in order to tell if it is a heap or not.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (1), the number of keys in the tree. Then the next line contains N distinct integer keys (all in the range of int), which gives the level order traversal sequence of a complete binary tree.
Output Specification:
For each given tree, first print all the paths from the root to the leaves. Each path occupies a line, with all the numbers separated by a space, and no extra space at the beginning or the end of the line. The paths must be printed in the following order: for each node in the tree, all the paths in its right subtree must be printed before those in its left subtree.
Finally print in a line Max Heap
if it is a max heap, or Min Heap
for a min heap, or Not Heap
if it is not a heap at all.
Sample Input 1:
8
98 72 86 60 65 12 23 50
Sample Output 1:
98 86 23
98 86 12
98 72 65
98 72 60 50
Max Heap
Sample Input 2:
8
8 38 25 58 52 82 70 60
Sample Output 2:
8 25 70
8 25 82
8 38 52
8 38 58 60
Min Heap
Sample Input 3:
8
10 28 15 12 34 9 8 56
Sample Output 3:
10 15 8
10 15 9
10 28 34
10 28 12 56
Not Heap
这道题题意:已知一个树,求根节点到叶子节点的每条路径遍历,并且判断是大根堆,小跟堆,还是不是堆
#include <iostream> #include <vector> int N, arr[1100]; int isHeap; using namespace std; void dfs(int root, vector<int> path) { path.push_back(arr[root]); if(2 * root + 2 < N) { if(isHeap == 1 && arr[root] < arr[2 * root + 2]) isHeap = -1; if(isHeap == 0 && arr[root] > arr[2 * root + 2]) isHeap = -1; dfs(2 * root + 2, path); } if(2 * root + 1 < N) { if(isHeap == 1 && arr[root] < arr[2 * root + 1]) isHeap = -1; if(isHeap == 0 && arr[root] > arr[2 * root + 1]) isHeap = -1; dfs(2 * root + 1, path); } if(2 * root + 1 >= N && 2 * root + 2 >= N) { if(path.size() != 0) printf("%d", path[0]); for(int i = 1; i < path.size(); i++) printf(" %d", path[i]); putchar('\n'); } } int main() { scanf("%d", &N); for(int i = 0; i < N; i++) scanf("%d", &arr[i]); isHeap = arr[0] > arr[1]; vector<int> path; dfs(0, path); // 0节点是否比1节点大, 大跟堆 1, 小跟堆 0, 不是堆 -1 if(isHeap == 1) printf("Max Heap\n"); else if(isHeap == 0) printf("Min Heap\n"); else printf("Not Heap\n"); return 0; }
标签:Paths,arr,heap,1155,30,isHeap,Heap,path,root 来源: https://www.cnblogs.com/littlepage/p/12817895.html