leetcode 297. Serialize and Deserialize Binary Tree
作者:互联网
Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another computer environment.
Design an algorithm to serialize and deserialize a binary tree. There is no restriction on how your serialization/deserialization algorithm should work. You just need to ensure that a binary tree can be serialized to a string and this string can be deserialized to the original tree structure.
Example:
You may serialize the following tree:
1
/ \
2 3
/ \
4 5
as "[1,2,3,null,null,4,5]"
Clarification: The above format is the same as how LeetCode serializes a binary tree. You do not necessarily need to follow this format, so please be creative and come up with different approaches yourself.
Note: Do not use class member/global/static variables to store states. Your serialize and deserialize algorithms should be stateless.
题目提供树形结构序列化和反序列化接口。
先序遍历是个好法子。代码如下:
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Codec:
def serialize(self, root):
"""Encodes a tree to a single string.
:type root: TreeNode
:rtype: str
"""
ret = []
def DLR(node,ret):
if node:
ret.append(str(node.val))
DLR(node.left,ret)
DLR(node.right,ret)
else:
ret.append(".")
DLR(root,ret)
return ",".join(ret)
def deserialize(self, data):
"""Decodes your encoded data to tree.
:type data: str
:rtype: TreeNode
"""
it = iter(data.split(","))
def DLR():
val = next(it)
if val == ".":
return None
root = TreeNode(int(val))
root.left = DLR()
root.right = DLR()
return root
return DLR()
# Your Codec object will be instantiated and called as such:
# codec = Codec()
# codec.deserialize(codec.serialize(root))
标签:node,Binary,Deserialize,self,Serialize,tree,ret,DLR,root 来源: https://blog.csdn.net/u011255131/article/details/104812209