1281. Subtract the Product and Sum of Digits of an Integer
作者:互联网
class Solution {
public:
int subtractProductAndSum(int n) {
int sum=0;
int multiple=1;
while(n!=0){
sum += n%10;
multiple *= n%10;
n = n/10;
}
//cout<<sum<<endl;
//cout<<multiple<<endl;
return multiple-sum;
}
};
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标签:Digits,10,Product,1281,int,sum,n%,文章,multiple 来源: https://blog.csdn.net/zeroQiaoba/article/details/104587843