从零开始的刷LeetCode生活 第26期 261-270

class Solution {
public:
    bool isUgly(int num) {
        if(num <= 0) return false;
        while(num % 5 == 0)
            num /= 5;
        while(num % 3 == 0)
            num /= 3;
        while(num % 2 == 0)
            num /= 2;
        return num == 1;
    }
};

class Solution {
public:
    int nthUglyNumber(int n) {
        vector<int>q;
        q.push_back(1);
        int i = 0, j = 0, k = 0;
        while(--n)
        {
            int t = min(q[i] * 2, min(q[j] * 3, q[k] * 5));
            q.push_back(t);
            if(q[i] * 2 == t) i ++;
            if(q[j] * 3 == t) j ++;
            if(q[k] * 5 == t) k ++; 
        }
        return q.back();
    }
};

class Solution {
public:
    int missingNumber(vector<int>& nums) {
        int sum = 0;
        for(auto x : nums) sum += x;
        return (0 + nums.size()) * (nums.size() + 1) / 2 - sum;
    }
};

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来源： https://blog.csdn.net/qq_42549254/article/details/104080085