Week08_day01 (Hive开窗函数 row_number()的使用 （求出所有薪水前两名的部门）)

数据准备：

7369,SMITH,CLERK,7902,1980-12-17,800,null,20
7499,ALLEN,SALESMAN,7698,1981-02-20,1600,300,30
7521,WARD,SALESMAN,7698,1981-02-22,1250,500,30
7566,JONES,MANAGER,7839,1981-04-02,2975,null,20,
7654,MARTIN,SALESMAN,7698,1981-09-28,1250,1400,30
7698,BLAKE,MANAGER,7839,1981-05-01,2850,null,30
7782,CLARK,MANAGER,7839,1981-06-09,2450,null,10
7788,SCOTT,ANALYST,7566,1987-04-19,3000,null,20
7839,KING,PRESIDENT,null,1981-11-17,5000,null,10
7844,TURNER,SALESMAN,7698,1981-09-08,1500,0,30
7876,ADAMS,CLERK,7788,1987-05-23,1100,null,20
7900,JAMES,CLERK,7698,1981-12-03,950,null,30
7902,FORD,ANALYST,7566,1981-12-03,3000,null,20
7934,MILLER,CLERK,7782,1982-01-23,1300,null,10

 在Hive中创建表（当然建表语句肯定不是这个，这个是字段）

使用本地加载命令加载数据 load data local inpath '文件的绝对路径' into table emp2;

查看

现在有一个需求：求出所有薪水前两名的部门。

第一步，使用开窗函数 row_number()进行分组编号‘降序使用 DESC

select deptno,sal,row_number() over(partition by deptno order by sal desc) from emp2;

 得到如下数据：

 再对其进行分组，取出编号小于3的数据得到结果：

select w.deptno,w.sal from (select deptno,sal,row_number() over(partition by deptno order by sal desc) as rn from emp2) w where w.rn<3;

标签：20,1981,Week08,30,number,Hive,deptno,null,7698
来源： https://www.cnblogs.com/wyh-study/p/12088320.html