入门模拟A1009 Product of Polynomials(25)
作者:互联网
2019-12-23
14:54:40
#include <bits/stdc++.h> #include<math.h> using namespace std; const int MAX_LEN = 2004; int main(){ double temp1[MAX_LEN]={0}; double temp2[MAX_LEN]={0}; int tem1; cin>>tem1; for(int i =0;i<tem1;++i){ int fir; double sec; cin>>fir; cin>>sec; temp1[fir] = sec; } int tem2; scanf("%d",&tem2); for(int i=0;i<tem2;++i){ int fir = 0; double sec = 0; cin>>fir; cin>>sec; temp2[fir] = sec; } double temp3[MAX_LEN] = {0}; int count = 0; for(int i =MAX_LEN;i>=0;--i){ for(int j=MAX_LEN;j>=0;--j){ if(temp1[i]==0){ break; } else{ if(temp2[j]!=0){ //count++; temp3[j+i] += (temp1[i]*temp2[j]); } } } } for(int i=MAX_LEN;i>=0;--i){ if(temp3[i]!=0&&i!=MAX_LEN){ count++; } } cout<<count; for(int i=MAX_LEN;i>=0;--i){ if(temp3[i]!=0&&i!=MAX_LEN){ printf(" %d %.1f",i,temp3[i]); } }
标签:25,Product,int,MAX,LEN,temp3,temp2,temp1,Polynomials 来源: https://www.cnblogs.com/JasonPeng1/p/12083770.html